Statics, friction of a rope around a post

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SUMMARY

The discussion centers on calculating the maximum tension (T) that a rope can support when a dockworker exerts a pull of 190 N on it, with the rope making 1.25 turns around a mooring bit. The coefficient of friction between the rope and the mooring bit is 0.35. The relevant equation is T2 = T1eμβ, where T2 represents the tension in the direction of impending motion. Participants clarify that T2 should be considered as the unknown tension (T) rather than the 190 N force exerted by the dockworker.

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  • Knowledge of tension forces in ropes and pulleys
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J-dizzal
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Homework Statement


A dockworker adjusts a spring line (rope) which keeps a ship from drifting alongside a wharf. If he exerts a pull of 190 N on the rope, which has 1.25 turns around the mooring bit, what force T can he support? The coefficient of friction between the rope and the cast-steel mooring bit is 0.35.
20150722_171921_zpszgrymvcs.jpg

Homework Equations


T2=T1eμβ
where T2 is in the direction of impending motion.

The Attempt at a Solution


20150722_171849_zpsf7gup5ud.jpg

Not sure what i am missing here, it looks right to me.
 
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J-dizzal said:
T2=T1eμβ
In this equation, which is the 190N, T1 or T2? Which did you try to solve for?

You should also run through the algebra again.
 
Nathanael said:
In this equation, which is the 190N, T1 or T2? Which did you try to solve for?

You should also run through the algebra again.
T2 is in the direction of impending motion, so i assumed it was 190N. Re reading the problem statement the ship is pulling on the rope with a much greater force, so then T2 would be T, the unknown.
Thank you Nathanael.
 
Last edited:
J-dizzal said:
T2 is in the direction of impending motion, so i assumed it was 190N. Re reading the problem statement the ship is pulling on the rope with a much greater force, so then T2 would be T, the unknown.
If the unknown force of tension were too large, it would cause the rope to slip towards it. We are asked for the maximum force of this unknown tension, so that means the unknown tension is the 'direction of impending motion.'

If you took T2 to be the 190N tension and solved it for T1 then what you would be calculating is the minimum force of tension the other side needs in order for the rope to not slip towards the dockworker.
 
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