- #1
Chacabucogod
- 56
- 0
Hi,
I was thinking about this and hit a "wall". If you have a vertical rod with constant area that is attached to the ceiling from one point its weight will be:
[itex]w(x)=ρ*x*g[\itex] (where 0 is the end of the bar)
now if you take a differential above x you will have that the downward force that it's experiencing is w(x), but above the dx is w(x+dx). Where did I go wrong here. Is there something I'm not taking into consideration?
Thank you.
I was thinking about this and hit a "wall". If you have a vertical rod with constant area that is attached to the ceiling from one point its weight will be:
[itex]w(x)=ρ*x*g[\itex] (where 0 is the end of the bar)
now if you take a differential above x you will have that the downward force that it's experiencing is w(x), but above the dx is w(x+dx). Where did I go wrong here. Is there something I'm not taking into consideration?
Thank you.