Statics Question: Finding Resultant Moment

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The discussion focuses on calculating the resultant moment produced by two forces about point O. The forces are broken down into their components: F1 has components F1x = 400 N and F1y = 300 N, while F2 has components F2x = 300 N and F2y = 519.62 N. The moments are calculated as MF1x = -100 Nm, MF1y = 127.5 Nm, MF2x = -75 Nm, and MF2y = -220.84 Nm, leading to a total moment of ƩM = -268.33 Nm, indicating a clockwise rotation. The confusion arises from the direction of the X components, which the user believes should cause a clockwise rotation.

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Chandasouk
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Determine the magnitude of the resultant moment produced by the forces about point O

Determine the direction of the resultant moment produced by the forces about point O

I first break the forces down to their components.

F1x = 500(4/5)

F1y=500(3/5)

F2x=600cos(60)

F2y=600sin(60)

The problem for me is when it comes time to add their moments. I am taking counter clockwise to be POSITIVE and clockwise to be NEGATIVE.

MF1x= -500(4/5)(0.25) = -100

MF1y= 500(3/5)(0.425) = 127.5

MF2x= -600cos(60) (0.25)=-75

MF2y= -600sin(60)(0.425) = -220.836478

so ƩM = -268.33 Nm turning clockwise?

The directions of the X components are confusing me, I would imagine they would cause the object to turn clockwise? I have only a few tries left on my HW so I just wanted to be sure of my answer.
 
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Your work looks good to me. (I don't see why you find the x components confusing.)
 

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