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Statics Question: Finding Resultant Moment

  1. Feb 21, 2013 #1
    http://img831.imageshack.us/img831/8005/f48am.jpg [Broken]

    Determine the magnitude of the resultant moment produced by the forces about point O

    Determine the direction of the resultant moment produced by the forces about point O

    I first break the forces down to their components.

    F1x = 500(4/5)

    F1y=500(3/5)

    F2x=600cos(60)

    F2y=600sin(60)

    The problem for me is when it comes time to add their moments. I am taking counter clockwise to be POSITIVE and clockwise to be NEGATIVE.

    MF1x= -500(4/5)(0.25) = -100

    MF1y= 500(3/5)(0.425) = 127.5

    MF2x= -600cos(60) (0.25)=-75

    MF2y= -600sin(60)(0.425) = -220.836478

    so ƩM = -268.33 Nm turning clockwise?

    The directions of the X components are confusing me, I would imagine they would cause the object to turn clockwise? I have only a few tries left on my HW so I just wanted to be sure of my answer.
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Feb 21, 2013 #2

    TSny

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    Homework Helper
    Gold Member

    Your work looks good to me. (I don't see why you find the x components confusing.)
     
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