http://img831.imageshack.us/img831/8005/f48am.jpg [Broken] Determine the magnitude of the resultant moment produced by the forces about point O Determine the direction of the resultant moment produced by the forces about point O I first break the forces down to their components. F1x = 500(4/5) F1y=500(3/5) F2x=600cos(60) F2y=600sin(60) The problem for me is when it comes time to add their moments. I am taking counter clockwise to be POSITIVE and clockwise to be NEGATIVE. MF1x= -500(4/5)(0.25) = -100 MF1y= 500(3/5)(0.425) = 127.5 MF2x= -600cos(60) (0.25)=-75 MF2y= -600sin(60)(0.425) = -220.836478 so ƩM = -268.33 Nm turning clockwise? The directions of the X components are confusing me, I would imagine they would cause the object to turn clockwise? I have only a few tries left on my HW so I just wanted to be sure of my answer.