Statics Question: Finding Resultant Moment

[Chandasouk]

http://img831.imageshack.us/img831/8005/f48am.jpg

Determine the magnitude of the resultant moment produced by the forces about point O

Determine the direction of the resultant moment produced by the forces about point O

I first break the forces down to their components.

F1_x = 500(4/5)

F1_y=500(3/5)

F2_x=600cos(60)

F2_y=600sin(60)

The problem for me is when it comes time to add their moments. I am taking counter clockwise to be POSITIVE and clockwise to be NEGATIVE.

MF1x= -500(4/5)(0.25) = -100

MF1y= 500(3/5)(0.425) = 127.5

MF2x= -600cos(60) (0.25)=-75

MF2y= -600sin(60)(0.425) = -220.836478

so ƩM = -268.33 Nm turning clockwise?

The directions of the X components are confusing me, I would imagine they would cause the object to turn clockwise? I have only a few tries left on my HW so I just wanted to be sure of my answer.

 

[TSny]

Your work looks good to me. (I don't see why you find the x components confusing.)