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**This is a piece of circuit:**

.

I

I

_{2}= 2A, I_{1}= 4A, R = 10[tex]\Omega[/tex], V_{B}- V_{C}= 12V. Find I_{y}(that goes over R_{y}), R_{x}, R_{y}and V_{A}- V_{D}## The Attempt at a Solution

I can find R

_{x}pretty easily, using that V

_{B}- V

_{C}= 12V, then, since V= IR, V

_{B}- 10 V - I

_{2}*R

_{x}- V

_{C}= 0.

I also find, using the same fact, that I

_{y}*R

_{y}= V

_{B}- V

_{C}= 12V (going through the lower branch that joins B and C).

But I can't see how I can get I

_{y}. I know that in B (node), there's I

_{1}and I

_{y}AND another current (be it I

_{3}) that should go towards the 10V battery next to B. I also

*believe*that I

_{2}= I

_{3}+ I

_{4}, where I

_{4}is current generated by the 10 V battery.

Now, I

*know*the last sentence must have something wrong with it, because in the exercise the first thing they ask to find is I

_{y}, so it should come out fast. My problem is that I have been having trouble with the currents and their directions (how to predict this).

My question is: can part of the current I

_{1}go through the battery and aid forming I

_{2}? What am I missing?

Thanks