Stationary distribution of countable Markov chain

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SUMMARY

The stationary distribution of a countable Markov chain with state space {0, 1, 2, ..., n, ...} is defined by the probabilities of each state. Specifically, the probability of being in state n is given by the formula P(n) = (1/2)^(n+1). This result is derived from the steady-state analysis of the Markov chain, where the transition probabilities allow for a return to state 0 with a probability of 1/2 and a transition to the next state with a probability of 1/2. As n approaches infinity, this distribution converges, confirming its validity.

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shoplifter
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How do I find the stationary distribution of the Markov chain with the countable state space {0, 1, 2, ..., n, ...}, where each point, including 0, can either

a. return to 0 with probability 1/2, or
b. move to the right n -> n+1 with probability 1/2?

Thanks.
 
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Prob. of state n = (1/2)^(n+1). This is obtained by calculation of steady state of
{0,1,..n} and letting n -> infinity.
 

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