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Statistical mechanics average energy

  • Thread starter sarahger9
  • Start date
  • #1
3
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Homework Statement



average energy per particle u = (Eo + E1 e^(-B deltaE)) / (1 + e^(-B deltaE))
B = 1/T


Homework Equations



Possibly relevant: e^x = 1 + x^2 / 2! + x^3 / 3! ......

The Attempt at a Solution



It tells me the average energy is about u = Eo + (deltaE)e^(-B delatE) as t approaches 0, and u = (1/2)(Eo + E1) - (1/4)B(delataE)^2 as T approaches infinity.

I can easily derive the first term in both of these equations, but the second is giving me some trouble. I tried to Taylor expand the exponential, but everything seems to cancel out and appear as before.
 

Answers and Replies

  • #2
kdv
340
4

Homework Statement



average energy per particle u = (Eo + E1 e^(-B deltaE)) / (1 + e^(-B deltaE))
B = 1/T


Homework Equations



Possibly relevant: e^x = 1 + x^2 / 2! + x^3 / 3! ......

The Attempt at a Solution



It tells me the average energy is about u = Eo + (deltaE)e^(-B delatE) as t approaches 0, and u = (1/2)(Eo + E1) - (1/4)B(delataE)^2 as T approaches infinity.

I can easily derive the first term in both of these equations, but the second is giving me some trouble. I tried to Taylor expand the exponential, but everything seems to cancel out and appear as before.

What is the question???
 
  • #3
3
0
Sorry, I am attempting to derive the solution that was given to me, the energy as T approaches 0 and infinity from the average energy per particle
 
  • #4
kdv
340
4
Sorry, I am attempting to derive the solution that was given to me, the energy as T approaches 0 and infinity from the average energy per particle
You might want to try the T-> infinity first. I got their answer. Just Taylor expand. And you will also need to use that

[tex]\frac{1}{1+x} \approx 1-x [/tex]

If you don't get it, post your steps
 

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