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sunrah
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Homework Statement
Individual hydrogen atoms have been prepared in the energy state n = 2. However, nothing is known about the remaining quantum numbers. Fine structure and all corrections can be ignored.
What is the micro-canonical statistical operator.
Homework Equations
[itex] \hat{\rho_{mc}} = \frac{1}{\Omega (E)}\delta(E-\hat{H})[/itex]
[itex] \hat{H} = -\frac{\hbar^{2}}{2m_{p}}\Delta_{p} -\frac{\hbar^{2}}{2m_{e}}\Delta_{e} - \frac{e^{2}}{4\pi \epsilon_{0}}\frac{1}{\left|r_{p} - r_{e}\right|}[/itex]
[itex] \Omega (E) = Tr( \delta(E-\hat{H}) )[/itex]
The Attempt at a Solution
I don't understand this. If the atoms are all in state n = 2 then with have a system in a pure state: therefore the probability [itex]p_{i} = \frac{1}{\Omega (E)} = 1[/itex] and [itex]\rho = |2\rangle \langle 2|[/itex].
is that so?
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