Statistics Problem: Thickness of gears and spacers

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SUMMARY

The discussion focuses on calculating the mean and standard deviation of the thickness of a five-gear assembly with four spacers. The mean thickness of the gears is 5.03 cm with a standard deviation of 0.008 cm, while the mean thickness of the spacers is 0.14 cm with a standard deviation of 0.005 cm. The total mean thickness of the assembly can be derived by summing the mean thicknesses of the gears and spacers. The standard deviation calculation involves the square root of the sum of the squares of the individual standard deviations.

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A five-gear assembly is put together with spacers between the gears. The mean thicnkess of the gears is 5.03 cm with a standard ev. of .008. the mean thickness of the spacers is .140 cm with a standard dev. of .005. Find the mean and standard deviation of the thickness of the assembled units consisting of five randomly selected gears and four randomly selected spacers.

I am kind of confused on where to even start since I don't truly understand what the problem is asking.
 
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Visualize the assembly! You have 5 gears with 4 spacers between them.
If you assume each gear is exactly 5.03 cm thick and each spacer is exactly 0.14 cm thick how thick would the whole assembly be?
Do you see how that's connected to the mean value of the thickness of the assembly?

To be more technical, if the probability density for the thickness of the gears is f(x) and the probability density for the thickness of the spacers is g(x) then the mean thickness of a gear is [itex]\mu_1=\int xf(x)dx[/itex] and the mean thickness of a spacer is [itex]\mu_2=\int xg(x)dx[/itex].
The mean thickness of a gear and a spacer together is [itex]\int x(f(x)+g(x))dx= \mu_1+ \mu_2[/itex].
The standard deviation of the thickness of the assembly is a little harder. Remember that standard deviation is defined in terms of "square root of a sum of squares".
 
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