Steady State output for Wave Input

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soccer4life
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1. Problem Statement
Find the steady state output yss(t) for the input u(t)=t-π in terms of an infinite sum of sinusoids.
We are given the transfer function as:
Transfer function G(s) equals s divided by 5s squared plus s plus 5.

2. Homework Equations

G(i) = ...
|G(ik)| = ...
Φ(ik) = ... (this is the angle)
yss(t) = βk||G(ik)|ei(kt+Φ(ik)) ***check that this is the correct formula please***

3. Attempt at Solution
I've found the following:
G(i)=1
|G(ik)| =
Formula for the magnitude of a transfer function: k divided by the square root of (25(1 - k^2)^2 + k^2).
(Any tips/tricks on how to input fractions/square roots into PF would be greatly appreciated...)
Φ(ik) =
Expression for an angle: 3π/2 + arctan(k / (5(1 − k²))), with k in the arctangent argument.


Previously, the Fourier Series expansion was found, and is: the sum from 1 to infinity of Σ-2sin(kt)/k

I know that these values are right. However, I don't fully understand how to incorporate them into the steady state formula (assuming that my formula is correct)
 
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  • Transfer function G(s) equals s divided by 5s squared plus s plus 5.
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  • Formula for the magnitude of a transfer function: k divided by the square root of (25(1 - k^2)^2 + k^2).
    199549-3d8b3d65837a235ecb2c36e83fa44816.png
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  • Expression for an angle: 3π/2 + arctan(k / (5(1 − k²))), with k in the arctangent argument.
    199551-ccce8e83197e676283b3561ae3b6c3be.png
    677 bytes · Views: 392
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Use the fact that ##\sin\theta = \frac{e^{i\theta}-e^{-i\theta}}{2i}##.