Calculating Heat Discharge in a Steam Engine: Efficiency and Work Rate Analysis

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In analyzing the heat discharge of a steam engine operating at half its theoretical maximum efficiency, it is established that the actual efficiency is 0.5, represented by the equation W/QH = 1/2. The heat discharged, denoted as QL, is calculated using the formula QL = QH - W. Since the engine is functioning at 50% efficiency, it discharges an equivalent of 1 J/s of heat. Additionally, the theoretical maximum efficiency for a heat engine is defined as 1 - TL/TH.
kasse
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Homework Statement



If a steam engine operates at half of its theoretical maximum efficiency, and does work at a rate of W J/s, calculate how much heat is discharged per second.


The Attempt at a Solution



emax = W/QH (Carnot)

emax = W/2QH

--> QH = W/emax

Wrong answer. What is my mistake?
 
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kasse said:

Homework Statement



If a steam engine operates at half of its theoretical maximum efficiency, and does work at a rate of W J/s, calculate how much heat is discharged per second.

The Attempt at a Solution



emax = W/QH (Carnot)

emax = W/2QH

--> QH = W/emax

Wrong answer. What is my mistake?

Theoretical max would be equal to 1, 50% would be the actual efficiency = .5 =W/QH=1/2. Heat discharged would be QL which equals QH-W. If the engine is operating at 50% efficiency, half the heat input will go to shaft work, the other half will be discharged. So this engine would discharge 1 J/s. BTW, theoretical max. for a heat engine is 1-TL/TH.
 

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