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- Thread starter Venomily
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- #3

jedishrfu

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Which sentence are you confused about?

Electronic calculators are not permitted? This just means you can't bring a calculator to use, you must use pencil and paper and the math tables they provide.

or are you talking about problem 13.

**EDIT: Oops missed the Question 5 reference. Disregard my response...**

Electronic calculators are not permitted? This just means you can't bring a calculator to use, you must use pencil and paper and the math tables they provide.

or are you talking about problem 13.

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- #4

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I don't know what equation I'll get. How do I make the substitution?

"Use the expression (**) to find A and B by

@Bolded, just what? how can i possibly 'substitute' f(t) and f(x) into (*)? if it means I set the expressions equal: [*] = [**] this doesn't yield anything.

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- #5

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Which sentence are you confused about?

Electronic calculators are not permitted? This just means you can't bring a calculator to use, you must use pencil and paper and the math tables they provide.

or are you talking about problem 13.

I said it at the top of the OP: question 5 .

- #6

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So, you need to solve for A and B in this equation:

Asin(t)+Bsin(t) = ∫(0->pi) [f(x) sin(x+t)]dx

Should be relatively simple. Just take the derivative of each side with respect to x, or you can parse out the integral of f(x)sin(x+t)... I would chose the first choice.

Edit: dont forget that A and B both have f(x) components if you try and take the derivative of the substituted equation.

- #7

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So, you need to solve for A and B in this equation:

Asin(t)+Bsin(t) = ∫(0->pi) [f(x) sin(x+t)]dx

Should be relatively simple. Just take the derivative of each side with respect to x, or you can parse out the integral of f(x)sin(x+t)... I would chose the first choice.

Edit: dont forget that A and B both have f(x) components if you try and take the derivative of the substituted equation.

I really don't see where this is going, both equations are identical:

This is the same thing as:

If I tried to differentiate I would just get:

sin(t)f(x)cos(x) dx + cos(t)f(x)sin(x) dx = f(x)sin(x+t) dx

You can't do anything with this equation.

- #8

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I think you are approaching the derivative wrong.

- #9

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I think you are approaching the derivative wrong.

please show me what you think the derivative should be.

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