- #1
haruspex said:What equation do you get if you make the substitutions suggested? Can you solve the integrals on the RHS? Having solved them, you will have expressions involving sin(t) and cos(t) on both sides. Treat this as two equations, one involving only the sin terms and one involving only the cos terms.
jedishrfu said:Which sentence are you confused about?
Electronic calculators are not permitted? This just means you can't bring a calculator to use, you must use pencil and paper and the math tables they provide.
or are you talking about problem 13.
johnkubik said:Basically, your second equation -- related to (**) -- into your first equation -- related to (*).
So, you need to solve for A and B in this equation:
Asin(t)+Bsin(t) = ∫(0->pi) [f(x) sin(x+t)]dxShould be relatively simple. Just take the derivative of each side with respect to x, or you can parse out the integral of f(x)sin(x+t)... I would chose the first choice.
Edit: don't forget that A and B both have f(x) components if you try and take the derivative of the substituted equation.
johnkubik said:I think you are approaching the derivative wrong.
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