1. The problem statement, all variables and given/known data A student has 4.00g of Copper Chloride (CuCl2) and 25.0 g of Aluminum (Al). Calculate the mass of each reactant and product present at the end of the reaction. Show your calculations. 2. Relevant equations 3 CuCl2 + 2Al [tex]\rightarrow[/tex] 3Cu + 2AlCl3 3. The attempt at a solution Ok. I already know that Copper Chloride is the limiting reactant, but I know how to prove it too. I have figured out the amount of Copper that would be produced from 4.00g of CuCl2 as 1.89g Cu. I have figured out that the amount of Copper that would be produced from 25.0 g of Al as 88.3g Cu. So, like I said.... CuCl2 is the limiting reactant. I also know that only 0.535g Al reacts with the 4.00 g of CuCl2. But- I honestly don't get what this question is actually asking me to do.... it's driving me nuts.