Stoiciometry. Finding mass and formula

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SUMMARY

The discussion focuses on a stoichiometry problem involving the reaction of 0.20 moles of an unknown compound CxHyNz with 60.7 g of O2, resulting in the production of 35.2 g of CO2 and 25.2 g of H2O. The calculated mass of the unknown compound is 18.1 g, with the empirical formula determined to be C4H14N2. The solution involves converting all quantities to moles, equating the coefficients of each element, and understanding the relationships between the compounds involved in the reaction.

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seru eman
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PROBLEM:
0.20 moles of C?H?N? + 60,7 g O2 --> 35,2 g CO2 + 25,2 g H2O + ? g NO2

how many grams of the molecule C?H?N? did we have before the reaction?

Find the formula.

ANSWER:
18,1g, C4H14N2

BUT:
how do you solve it?

Thanks in advance!
 
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seru eman said:
PROBLEM:
0.20 moles of C?H?N? + 60,7 g O2 --> 35,2 g CO2 + 25,2 g H2O + ? g NO2

how many grams of the molecule C?H?N? did we have before the reaction?

Find the formula.

ANSWER:
18,1g, C4H14N2

BUT:
how do you solve it?

Thanks in advance!

Try it mathematically. Start by making everything in the same units, e.g. all in moles. Then compare the coefficents of each compound that contains the same element, e.g. Equate the carbons - 0.2 Cx = 0.8 C. Then think about elements and how they work, e.g. if you have 2CO2 this is the same as saying there are 2 carbon atoms and 4 oxygen atoms or C2O4. Obvious the mole contains more than just one molecule of a substance, which is what I am implying, but it will allow you to make this relationship that will help you to solve the problem. If it really gets to you, say that 2 moles of CO2 is the same as 1 mole of C2O4.

From the equation, I originally wrote, x = 4, which is the number of carbon atoms you need per mole (as per your solutions), as 0.8 C = 0.2 Cx = 0.2x C (if we use the logic from earlier).

Hope this helps with the solution, not necessarily the chemistry.

The Bob (2004 ©)

P.S. I reckon the mass of NO2 is 18.3g not 18.1g :biggrin:
 
Last edited:

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