Stone thrown at 45° on a 5° downward slope

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Atilla1982
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2d Motion

I've been stuck with this problem for a while. Appreciate if anyone can point me in the right direction.

A boy stands in a field, he throws a stone with an initial 45 degree angle. The field has a 5 degree angle downwards, so the stone touches down at -5 degree angle and 82 meters away. g=9,8m/s^2

Find the time (t) for the entire throw, and the initial velocity (v0) for the stone.
 
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sin45*v0*t=82*cos50
sin45*v0=g*t1
2*t1+t2=t
sin45*v0*t2+0.5*g*t2^2=82*sin50

4 equations for 4 unknows

we use the symmetry of the motion, and the independence of the motions in different directions
 
sorry, cos50 and sin50 above mean cos5 and sin5
 
and you can also use energy , but i don't think it woulb be much more easier
 
couldn't i do: R=Vi^2*sin2(THETAi)/g

R=the length of the throw

Solving for Vi= 21.72 m/s
 
And then set up an integral for time?