(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A parallel plate is connected to one battery and has a material with a dielectric constant of 1.57 filling the space between the plates. The stored energy for the parallel plate capacitor is 21.6 Joules. While connected to the same battery the distance between the plates is decreased by a multiple of 2.3 and the dielectric is removed so that there is nothing between the plates. What is the stored energy in the capacitor now in Joules?

2. Relevant equations

C= K Enot A / d

Co= C/ K

U = 1/2 QV, or Q^2 / 2c

3. The attempt at a solution

I'm not really sure where to go on this problem. Do I have to somehow find the voltage of the battery and do something with that? Or maybe the C or Q? thanks.

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# Homework Help: Stored Energy In a Capacitor

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