Straight Line Distance from D to A: Calculating with Pythagorean Theorem

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Homework Help Overview

The problem involves calculating the straight line distance from point D to point A after a vehicle travels a specific path. The subject area is geometry, specifically the application of the Pythagorean theorem in a coordinate context.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formation of a right triangle based on the vehicle's path and question how to identify the relevant sides for applying the Pythagorean theorem. Some express uncertainty about visualizing the triangle and its components.

Discussion Status

There is an ongoing exploration of how to set up the problem geometrically. Some participants have provided guidance on drawing the necessary lines to visualize the triangle, while others are still clarifying their understanding of the setup.

Contextual Notes

One participant mentions a lack of recent math experience and challenges with the provided textbook, which may affect their confidence in tackling the problem.

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Homework Statement


Vehicle drives from a to b (south 100mi), then from b to c (east 200mi), then from c to d (north 300mi). What is the straight line distance from d to a?


Homework Equations


Not sure. Maybe Pythagorean theorem.


The Attempt at a Solution


No idea really. I drew a diagram and labeled it and that's about as far as I got. Thanks.
 
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Yes you will have a right angle triangle. You can figure out the lengths of two of the sides based on the information given in the question. Then use the Pythagorean theorem to get the hypontenuse. Where are you getting stuck?
 
Well, I have not had a math course in about 15 years and this is my first time taking physics. The text that I have for my class is not that good as far as showing examples of how to do things. I drew the diagram and it has 3 given sides, then to find the distance it would be a 4th side, so how do you get a triangle out of it?
 
Draw a line from point a across to the line cd (keep it perpendicular to cd).
 
OK. Gotcha. Now we have a right triangle. Didnt see it at first. Thanks a lot.
 
Last edited:

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