Straight Line Kinematics Problem

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SUMMARY

The discussion centers on a physics problem involving a baseball pitcher throwing a ball at a speed of 47 m/s and the subsequent acceleration experienced by the ball as it is caught by the catcher. Using the equation v² = v₁² + 2ad, the calculated acceleration is 31,557 m/s², which raises concerns about its realism. Participants confirm that such a high acceleration is expected due to the short distance of 0.035 m over which the ball is caught, emphasizing the need to compare the resulting force with the weight of an object for context.

PREREQUISITES
  • Understanding of basic kinematics principles
  • Familiarity with the equation of motion v² = v₁² + 2ad
  • Knowledge of force and mass relationships (Newton's Second Law)
  • Basic understanding of units of measurement in physics (m/s, m/s²)
NEXT STEPS
  • Research the implications of high acceleration in sports physics
  • Learn about Newton's Second Law and its applications in real-world scenarios
  • Explore the concept of impulse and momentum in catching sports balls
  • Investigate the physics of projectile motion and its relevance to baseball
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as coaches and athletes interested in understanding the dynamics of ball sports.

cvc121
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Homework Statement


[/B]
A baseball pitcher throws a ball at a speed of 47m/s. When the catcher receives the ball, he pulls his hand back through a distance of 0.035m in the process of making the catch. What was the acceleration of the ball as it was being caught, assuming the acceleration was constant. What was the acceleration of the ball as it was being caught?, assuming the acceleration was constant.

Homework Equations



v22 = v12 + 2ad

The Attempt at a Solution



472 = 02 + 2(a)(0.035)
a = 472 / (2)(0.035)
a = 31557 m/s2

*I think my answer is totally unrealistic. I am not sure how to deal with the hand being pulled back 0.035m in the process of making the catch. Do I also need to calculate the distance traveled before making the catch?

Thanks! All help is very much appreciated!
 
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You answer is correct. What makes you think it isn't? The balls going around 170 km/hr, To stop in just 35 mm takes tremendous acceleration.

cvc121 said:
Do I also need to calculate the distance traveled before making the catch?
There's no way to do that. You don't have enough information.
 
To assess how realistic it is, determine the force. I gather a baseball has a mass of around 0.15kg. Compare the force with the weight of something.
 

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