1. The problem statement, all variables and given/known data A baseball pitcher throws a ball at a speed of 47m/s. When the catcher receives the ball, he pulls his hand back through a distance of 0.035m in the process of making the catch. What was the acceleration of the ball as it was being caught, assuming the acceleration was constant. What was the acceleration of the ball as it was being caught?, assuming the acceleration was constant. 2. Relevant equations v22 = v12 + 2ad 3. The attempt at a solution 472 = 02 + 2(a)(0.035) a = 472 / (2)(0.035) a = 31557 m/s2 *I think my answer is totally unrealistic. I am not sure how to deal with the hand being pulled back 0.035m in the process of making the catch. Do I also need to calculate the distance travelled before making the catch? Thanks! All help is very much appreciated!