Straight wire inductance vs wire radius

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SUMMARY

The discussion centers on the relationship between straight wire inductance and wire radius, highlighting Rosa's derivation which establishes an inverse correlation between inductance and wire radius. Thinner wires allow for closer proximity of current filaments, enhancing magnetic field coupling, while thicker wires result in greater separation and reduced coupling. The conversation also touches on the implications for DC currents and the challenges of understanding Maxwell's Geometric Mean Distance in this context. Baluncore's visualization aids in comprehending the mutual inductance dynamics as wire diameter changes.

PREREQUISITES
  • Understanding of inductance principles in electrical engineering
  • Familiarity with Rosa's derivation of inductance
  • Knowledge of magnetic field coupling in current filaments
  • Basic grasp of Maxwell's Geometric Mean Distance
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  • Research the implications of wire radius on inductance in AC circuits
  • Study the effects of skin depth on high-frequency signals in conductors
  • Explore advanced concepts in mutual inductance and its calculations
  • Investigate practical applications of Rosa's work in modern electrical engineering
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Electrical engineers, physicists, and students studying electromagnetic theory, particularly those interested in inductance and its practical applications in circuit design.

supernano
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TL;DR
I am looking for an intuitive explanation to why the inductance of a straight wire is larger for thinner wires.
I know that the whole topic of inductance in a straight wire is complicated (and has led to some heated discussions in this forum :smile:). I followed Rosa's derivation and can see that it leads to an inverse relation of the inductance to the wire radius, and from what could understand, the point is that with thinner wires there is more "space" between the edge of the wire and infinity to integrate across. Is that it, or does someone have a better intuitive explanation for this relationship?
 
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Start by thinking of say 6 parallel filaments on the surface of the wire.

The filaments of current flowing on the thin wire are close together, so their magnetic fields have good coupling. On thicker wires, the individual filaments are more separated, so are less well coupled.

Then increase the number of filaments until you are thinking of a current sheet on the surface of a round wire.
 
Baluncore said:
Start by thinking of say 6 parallel filaments on the surface of the wire.

The filaments of current flowing on the thin wire are close together, so their magnetic fields have good coupling. On thicker wires, the individual filaments are more separated, so are less well coupled.

Then increase the number of filaments until you are thinking of a current sheet on the surface of a round wire.
Thanks @Baluncore, so I thought about this as well and it makes sense for high frequency signals where the skin depth is much smaller than the radius of the wire.. but from what I understand, Rosa's derivation applies to DC currents, which is what makes it less intuitive to me
 
supernano said:
.. but from what I understand, Rosa's derivation applies to DC currents, which is what makes it less intuitive to me
OK, so add a central filament, to the six peripheral filaments, making seven. Allocate one seventh of the sectional area to each filament. Place the filaments at the geometric mean of the sub-area they represent. The concept then fits the DC model, and the exact same logic follows. As the wire diameter is increased, the coupling between the filaments is reduced.
 
Baluncore's visualization of filaments of current within the wire leads us in the right direction. The mutual inductance between filaments increases as the wire diameter shrinks. (If the filament separation and total current in the wire are both held constant, then the current per filament increases, increasing the magnetic coupling.)
 
Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

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