String Vibrations: Determine Wavelength & Fundamental Frequency

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SUMMARY

The discussion focuses on calculating the wavelength and fundamental frequency of a standing wave in a 120-cm-long string fixed at both ends, vibrating in four segments at a frequency of 120Hz. The wavelength is correctly calculated using the formula Lambda = 2L/n, resulting in a wavelength of 60cm. The fundamental frequency can be determined using the relationship between frequency and wavelength, confirming the calculations are accurate.

PREREQUISITES
  • Understanding of standing waves
  • Knowledge of wave equations, specifically Lambda = 2L/n
  • Familiarity with frequency and its relationship to wavelength
  • Basic principles of wave mechanics
NEXT STEPS
  • Research the relationship between frequency and wavelength in wave mechanics
  • Learn about harmonic frequencies in strings and their calculations
  • Explore the effects of tension and mass per unit length on wave properties
  • Study the concept of resonance in fixed-end strings
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Students studying physics, particularly those focusing on wave mechanics, as well as educators looking for examples of standing wave calculations in strings.

Husker70
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Homework Statement


A standing wave is established in a 120-cm-long string fixed at both
ends. The string vibrates in four segments when driven at 120Hz.
(a) Determine the wavelength
(b) What is the fundamental frequency of the string?

Homework Equations


(a) Lambda = 2L/n


The Attempt at a Solution


(a) Lambda = 2(120cm) / 4 = 60cm

Is this right? doesn't seem to be
Kevin
 
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Hi Husker70,

Husker70 said:

Homework Statement


A standing wave is established in a 120-cm-long string fixed at both
ends. The string vibrates in four segments when driven at 120Hz.
(a) Determine the wavelength
(b) What is the fundamental frequency of the string?

Homework Equations


(a) Lambda = 2L/n


The Attempt at a Solution


(a) Lambda = 2(120cm) / 4 = 60cm

Is this right? doesn't seem to be

That looks right to me.
 

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