"structure" on the cosets → normal?

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SUMMARY

The discussion centers on the conditions under which a subgroup \( H \) of an infinite group \( G \) is normal, particularly when there exists an element \( g \in G \) such that the set \( \{g^n: n\in\mathbb{Z}\} \) serves as a transversal for the quotient group \( G/H \). It is concluded that \( H \) is not necessarily normal in \( G \), as illustrated by the example of the subgroup \( \mathbb{Z}/2 \) within the infinite dihedral group \( G = \langle u,t\ |\ u^2=1,\ utu=t^{-1} \rangle \), where \( H = \{1,u\} \) and \( g = t \).

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  • Familiarity with transversals in group theory.
  • Knowledge of the infinite dihedral group and its properties.
  • Basic understanding of subgroup structures and cosets.
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  • Study the properties of normal subgroups in group theory.
  • Learn about transversals and their applications in group theory.
  • Investigate the structure and properties of the infinite dihedral group.
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Mathematicians, particularly those specializing in abstract algebra, group theorists, and students seeking to deepen their understanding of subgroup structures and normality conditions in infinite groups.

Swlabr1
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Let $H\leq G$, where $G$ is some infinite group, and there exists some $g\in G$ such that the set $\{g^n: n\in\mathbb{Z}\}$ is a transversal for $G/H$. Then is $H$ normal in $G$?

I suspect not. However, I cannot seem to find a counter-example.

(By "a transversal for $G/H$" I mean that

1) $g^nH=g^mH\Rightarrow m=n$

2) if $hH$ is a coset of $G/H$ then there exists some $n\in\mathbb{Z}$ such that $g^nh^{-1}\in H$

so the powers of $g$ form a set of coset representatives for $G/H$, and no two of these representatives lie in the same coset.)
 
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Re: "structure" on the cosets $\Rightarrow$ normal?

Swlabr said:
Let $H\leq G$, where $G$ is some infinite group, and there exists some $g\in G$ such that the set $\{g^n: n\in\mathbb{Z}\}$ is a transversal for $G/H$. Then is $H$ normal in $G$?

I suspect not. However, I cannot seem to find a counter-example.

(By "a transversal for $G/H$" I mean that

1) $g^nH=g^mH\Rightarrow m=n$

2) if $hH$ is a coset of $G/H$ then there exists some $n\in\mathbb{Z}$ such that $g^nh^{-1}\in H$

so the powers of $g$ form a set of coset representatives for $G/H$, and no two of these representatives lie in the same coset.)

Hi Swlabr, :)

Does \(G/H\) stands for the quotient group ? In that case all the other parts of the question are redundant since by definition of quotient groups \(H\) should be normal in \(G\).

Kind Regards,
Sudharaka.
 
Re: "structure" on the cosets $\Rightarrow$ normal?

What about the (non-normal) subgroup $\mathbb{Z}/2$ as a subgroup of the infinite dihedral group? More precisely, let $G = \langle u,t\ |\ u^2=1,\ utu=t^{-1} \rangle$. Let $H = \{1,u\}$, and take $g=t$ for the generator of the transversal.
 

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