adelin Messages 32 Reaction score 0 Thread starter Feb 14, 2014 #1 I cannot find a substitution that work for this integral ∫dx/2√x+2x what should I do?
statdad Homework Helper Messages 1,549 Reaction score 99 Feb 14, 2014 #2 What is [itex]\left(\sqrt{x}\right)^2[/itex]?
PhysicoRaj Gold Member Messages 538 Reaction score 49 Feb 14, 2014 #4 See what you can do to bring a function and it's derivative.. you have √x in the denominator so you should think in terms of derivative of that.
See what you can do to bring a function and it's derivative.. you have √x in the denominator so you should think in terms of derivative of that.
statdad Homework Helper Messages 1,549 Reaction score 99 Feb 14, 2014 #5 If the integral is [tex] \int \frac{1}{2 \sqrt{x} + 2x} \, dx[/tex] thinking about the derivative of [itex]\sqrt{x}[/itex] alone will not help.
If the integral is [tex] \int \frac{1}{2 \sqrt{x} + 2x} \, dx[/tex] thinking about the derivative of [itex]\sqrt{x}[/itex] alone will not help.
PhysicoRaj Gold Member Messages 538 Reaction score 49 Feb 14, 2014 #7 If he tries to bring the derivative of √x so that it is in product with the original function √x, he can substitute easily. That's what I meant.
If he tries to bring the derivative of √x so that it is in product with the original function √x, he can substitute easily. That's what I meant.
PhysicoRaj Gold Member Messages 538 Reaction score 49 Feb 14, 2014 #8 Convert the addition form in the denominator into product form so that the function and it's derivative are seen clearly in multiplied form.
Convert the addition form in the denominator into product form so that the function and it's derivative are seen clearly in multiplied form.
vanhees71 Science Advisor Education Advisor Insights Author Messages 24,488 Reaction score 15,063 Feb 14, 2014 #9 Then think about the obvious substitution, aiming to get rid of the square root :-).