Solving a Line Integral Problem: Struggling for the Right Answer

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Homework Help Overview

The discussion revolves around a line integral problem involving parametric equations of a curve. The original poster expresses difficulty in obtaining the correct answer, suspecting a straightforward nature to the question.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the line integral formula using given parametric equations but questions their calculation of the integral and the resulting value. Some participants provide feedback on the calculations, particularly regarding the expression for the magnitude of the derivative vector.

Discussion Status

Participants are actively engaging with the original poster's calculations, offering clarifications and questioning specific steps. There is an ongoing exploration of the gradient of the function involved, indicating a productive direction in the discussion.

Contextual Notes

There is mention of an answer key discrepancy, with the original poster's calculated result differing from the expected answer. The range of integration is specified, and there are indications of potential miscalculations in the expressions used.

galaxy_twirl
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Hi everyone. I ran into a minor problem while trying to solve a problem on line integral. I suspect this question to be very straight-forward as it gave the parametric equations of the curve C. However, I am still unable to get the answer for some reason. May I have someone to point out where I went wrong? Thanks!

Question:

Ah, the image didn't get uploaded.. Please refer to the attached image. Thanks! The question in question is Q1(a).

My attempt:

Since x = t2 + 1 and y = t3+t , we have x(t) and y(t). Following on, I went one to apply the formula, ∫ F⋅ dr = ∫ f(x(t), y(t))||r'(t)|| dt.

I had r(t) as (t2 + 1) i + (t3+t) j. And I have r'(t) = (2t) i + (3t2 + 1) j, and ||r'(t)|| = √ (9t2 + 1)(t2 + 1).

Since the range of t is 0 ≤ t ≤ 1, I integrated over this range and my calculator returned 3.73 as the answer, but the answer in my answer key wrote 6. May I know where I had gone wrong? Thanks! :D

<In case the picture cannot be seen, I have uploaded it here.> Thanks again!
 

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galaxy_twirl said:
Hi everyone. I ran into a minor problem while trying to solve a problem on line integral. I suspect this question to be very straight-forward as it gave the parametric equations of the curve C. However, I am still unable to get the answer for some reason. May I have someone to point out where I went wrong? Thanks!

Question:

Ah, the image didn't get uploaded.. Please refer to the attached image. Thanks! The question in question is Q1(a).

My attempt:

Since x = t2 + 1 and y = t3+t , we have x(t) and y(t). Following on, I went one to apply the formula, ∫ F⋅ dr = ∫ f(x(t), y(t))||r'(t)|| dt.

I had r(t) as (t2 + 1) i + (t3+t) j. And I have r'(t) = (2t) i + (3t2 + 1) j, and ||r'(t)|| = √ (9t2 + 1)(t2 + 1).
Your r'(t) looks fine, but |r'(t)| doesn't.
galaxy_twirl said:
Since the range of t is 0 ≤ t ≤ 1, I integrated over this range and my calculator returned 3.73 as the answer, but the answer in my answer key wrote 6. May I know where I had gone wrong? Thanks! :D

<In case the picture cannot be seen, I have uploaded it here.> Thanks again!
 
Can you show me your work on the finding the gradient of f?
 
To Mark44: Oh dear. I must have been hallucinating when doing Math at nearly 3am. T_T Sorry. ||r'(t)|| is √(t^2 + (1/9))(t^2 + 1).

To td21: How do I find the gradient of f? Do I just use the formula Gradient = (y2-y1)/(x2-x1)?
 
However, my calculator returned 1.24 as the answer.. :/
 

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