Stuck on simple constant accel. problem

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SUMMARY

The discussion focuses on solving a physics problem involving an antelope moving with constant acceleration over a distance of 70.0 meters in 7.00 seconds, reaching a speed of 15 m/s at the second point. The key equations of motion with constant acceleration are provided, including Vx=Vox+AxT and Vx²=Vox²+2Ax(X-Xo). The user expresses difficulty in calculating the initial speed and acceleration, specifically struggling with the concept of average versus instantaneous velocity. The solution requires applying the equations of motion correctly to find the initial velocity and acceleration.

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  • Understanding of kinematic equations for constant acceleration
  • Familiarity with concepts of average and instantaneous velocity
  • Basic knowledge of algebra and solving equations
  • Access to "University Physics 11th edition" for reference
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  • Review the derivation and application of kinematic equations
  • Practice problems involving constant acceleration scenarios
  • Learn how to calculate instantaneous velocity from average velocity
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Students studying physics, particularly those focusing on kinematics, educators teaching motion concepts, and anyone looking to improve their problem-solving skills in physics-related topics.

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1. An antelope moving with constant acceleration covers the distance between two points 70.0 meters apart in 7.00 seconds. It's speed as it passes the second point is 15 m/s.
A] Find speed at first point. B] What is the acceleration?




2.
From text University Physics 11th edition question 2.21 page 70
Eqns of motion with constant acceleration
Vx=Vox+AxT
X=Xo+VoxT+1/2AxT
Vx2=Vox2+2Ax(X-Xo)
X-Xo=((Vox+Vx)/2)T




3. I have tried but nothing worth posting. I'm stuck on the fact that I cannot find how to use the average Velocity to find the instantaneous Velocity at point 1, Thank you!.
 
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You know T, Vx, and (X - X0). One of the four equations will allow to to determine V0x directly.
 
Crap! For some reason I was stuck on having to find the original velocity by finding the limit as time went down to zero... So I was plugging in 0.01, 0.001 and was getting ridiculous answers. Thank you! I've posted one more problem I cannot seem to get my head around.
 

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