Completely stumped on this one -- Kinematic Conceptual problem

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Homework Help Overview

The problem involves a scenario where a driver at a stoplight must accelerate forward to avoid being rear-ended by a car approaching from behind at constant velocity. The context is rooted in kinematics, focusing on motion, velocity, and acceleration without the introduction of forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to create variables for unknowns and explore equations connecting them. Some suggest plotting position versus time for both cars to visualize their motion. Questions arise regarding the interpretation of the equations of motion and the meaning of initial positions.

Discussion Status

Participants are actively engaging with the problem, seeking clarification on concepts and equations. Some have provided guidance on how to approach the problem through graphical representation and the relationship between the two cars' motions. There is a mix of understanding and confusion, particularly regarding the initial conditions and the implications of the equations used.

Contextual Notes

Participants note that the problem must be solved using only the material covered prior to the introduction of forces, which may limit the approaches available. There is also a recognition of the need for further clarification on the equations and their implications in the context of the problem.

  • #31
DoctorPhysics said:
I'm just going off an assumption here. Could it be because Xo is prior to your starting point? So anything g behind your initial position is negative?

Of course. Surely you must have seen a "number line" before? East = positive ##x##, west = negative ##x##.

number_line.gif
 

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  • #32
Now that the problem has been marked "solved", I can contribute a quicker way to get to the answer. The required distance ##x_{min.}## will depend on two independent parameters, the constant speed ##v_0## of the trailing car and the maximum acceleration ##a## of the leading car. The leading car must reach speed ##v_0## over the minimum distance ##x_{min.}##. If it moves slower than that, it started accelerating too late; if it moves faster than that, it started accelerating too soon. Therefore, from the "fourth" kinematic equation $$2ax_{min.}=v_0^2 - 0^2 \rightarrow x_{min.}=\frac{v_0^2}{2a}$$
 
  • #33
kuruman said:
Now that the problem has been marked "solved", I can contribute a quicker way to get to the answer. The required distance ##x_{min.}## will depend on two independent parameters, the constant speed ##v_0## of the trailing car and the maximum acceleration ##a## of the leading car. The leading car must reach speed ##v_0## over the minimum distance ##x_{min.}##. If it moves slower than that, it started accelerating too late; if it moves faster than that, it started accelerating too soon. Therefore, from the "fourth" kinematic equation $$2ax_{min.}=v_0^2 - 0^2 \rightarrow x_{min.}=\frac{v_0^2}{2a}$$
C.f. post #23.
 
  • #34
haruspex said:
C.f. post #23.
Sure, but it's not necessary to run time backwards. In either car's reference frame the other car drops its speed from initial speed ##v_0## to zero over distance ##x_{min.}##.
 
  • #35
kuruman said:
Sure, but it's not necessary to run time backwards. In either car's reference frame the other car drops its speed from initial speed ##v_0## to zero over distance ##x_{min.}##.
Yes, it is not necessary to run time backwards; I was just trying to make it exactly like the commonest example of the equation.
 

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