Stuck on this dimensional analysis question.

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Homework Help Overview

The problem involves dimensional analysis related to the total power radiated by an oscillating electric dipole, which depends on oscillation frequency, dipole moment, speed of light, and permittivity of free space. The original poster attempts to derive a functional form for power and subsequently find the ratio of power emitted at different frequencies.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the dimensional analysis of various physical quantities and their relationships. The original poster expresses confusion about determining the powers of different units and how to approach the second part of the problem regarding the ratio of power at different frequencies.

Discussion Status

Some participants provide guidance on unit conversion and suggest checking the signs of exponents. The discussion includes attempts to clarify the implications of doubling the frequency on the power function, with some participants exploring the mathematical relationships involved.

Contextual Notes

There is mention of potential confusion regarding the application of dimensional analysis and the interpretation of the problem's requirements, particularly in the context of deriving ratios from functional forms.

LiamG_G
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Homework Statement


The total power radiated by an oscillating electric dipole is a function of the oscillation frequency ω, the dipole moment p(=Qd, where ±Q is the charge at each end of the dipole and d is the distance between charges), the speed of light c and the permittivity of free space ε0. Apply dimensional analysis to find the form of this function. Hence find the ratio of the power emitted by the same dipole at frequencies ω and 2ω

Homework Equations


The Attempt at a Solution


I started off by writing out the units and trying to find the powers, this left me with:
J/s ∝ (Hz)A (Qm)B (m/s)C (F/m)D
My first thought was that C=1, so that there is s-1 on each side.
Then I thought that D=2 so that the metres cancel out.
Then I'm left with J ∝ (Hz)A Q F2 /s
And now I'm completely stuck :(
Any help appreciated, thanks.
 
Last edited:
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Hz = s-1.
You cannot start with seconds like that. Actually, it is pointless to start with seconds, as you can always adjust A. Start with something different. It is also useful to express F in different units.
 
I always seem to forget the simple things :(
Thanks for the help

So by converting everything to SI units I got A=-4, B=2, C=-3, D=-1
I got this from:
kgm2s-3 = (s-1)A (Asm)B (ms-1)C (s4A2m-3kg-1)D
D is the only one dealing with kg, so that must equal -1.
Then B must equal 2 so that A is canceled out.
Then C=-3 to bring m down to m2.
A must equal -4 to achieve s-3.

This leaves me with P = (p2)/(ω4c3ε)

I'm not sure how to tackle the second bit about the ration of ω and 2ω, I don't really understand what it's asking me to do. Can you please help?
 
Check the sign of the exponent A. Apart from that, it looks good (WolframAlpha can check this, for example).

Concerning (b), imagine you have a function f(x)=x2. If you double x (if you replace x by 2x), what happens to the function value?
 
Ah thank you very much.
I probably wouldn't have noticed that I got the sign wrong :(

If f(x)=x2 then f(2x)=4x2
So the ratio of the power at frequencies ω and 2ω would be 4
 
ah but as A=4, f(x)=x4, so f(2x)=16x4. Would that be correct? The ratio is 16?
 
LiamG_G said:
ah but as A=4, f(x)=x4, so f(2x)=16x4. Would that be correct? The ratio is 16?
Right.
 

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