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Stuck with this non-trivial algebra, solving for x

  1. Nov 5, 2016 #1
    1. The problem statement, all variables and given/known data
    I am trying to solve for x in this equation:
    upload_2016-11-5_20-20-12.png

    2. Relevant equations


    3. The attempt at a solution
    I tried solving it like a quadratic equation.
    This is the most simplified I could get it.
    upload_2016-11-5_20-18-4.png
    Can someone please help me find a simpler expression
     
  2. jcsd
  3. Nov 5, 2016 #2

    berkeman

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    Can you please show all of your work and intermediate steps? Thanks. :smile:
     
  4. Nov 5, 2016 #3

    Ray Vickson

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    Maybe there isn't a simpler expression. Not all simple-looking problems have simple-looking solutions. Anyway, I get a different answer.
     
    Last edited: Nov 5, 2016
  5. Nov 6, 2016 #4

    haruspex

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    A useful habit is to check whether a simple solution to the one expression is also a solution to the other. Your original has the solution x=a=c. That does not appear to be a solution of your final expression.
     
  6. Nov 6, 2016 #5
    upload_2016-11-6_11-6-28.png
    and then i just simplified to my final answer
     
  7. Nov 6, 2016 #6

    micromass

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    Third step, shouldn't it be ##\frac{c^2m^2}{b^2}## instead of ##c^2m^2##?
     
  8. Nov 6, 2016 #7

    PeroK

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    I would have multiplied through the first equation by ##a^2b^2## to get rid of the fractions.
     
  9. Nov 6, 2016 #8

    haruspex

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    Did you read post #4? You can make further use of this by plugging in the simple solution at various points in your working to see at what point it ceases to be a solution.
     
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