Sturm-Liouville Problem, boundary condition

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SUMMARY

The discussion centers on the Sturm-Liouville (SL) problem and its boundary conditions, specifically examining the Wronskian of eigenfunctions psi_m and psi_n. It is established that the Wronskian must equal zero for the boundary conditions to hold true. The user questions the implications of having a non-zero Wronskian in a set S, where W[psi_m(x), psi_n(x)] ≠ 0, and whether this scenario affects the validity of the SL conditions. The relationship between the parameters alpha and alpha' is also clarified, with alpha' defined as alpha_2 and alpha as alpha_1.

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  • Understanding of Sturm-Liouville theory
  • Familiarity with eigenfunctions and eigenvalues
  • Knowledge of the Wronskian determinant
  • Basic concepts of boundary value problems
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  • Study the properties of the Wronskian in the context of Sturm-Liouville problems
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Mathematicians, physicists, and engineering students focusing on differential equations, particularly those studying Sturm-Liouville theory and boundary value problems.

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46843bd5250780c5b80f9ce7cedb4a94.png


given the generalized SL conditions

260895bbe02b9032a667ce60edb101dd.png

10259e92b5c3019525bafbb12ef45065.png
diff87.png


Let's say psi_m and psi_n are eigenfunctions of the given y.
Its Wronskian is 0 because otherwise the boundary condition doesn't make sense much.

However, I wonder if it is possible to have,
S={ x | W[psi_m(x) , psi_n(x)] =/= 0 }
otherwise W[psi_m(x) , psi_n(x)] = 0
then alpha and alpha' are 0 at such points, but still satisfies SL conditions.
Would it matter because at those points we can have any psi_m(x) and psi_n(x)?

If not could anyone tell me why?
 
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ah, forgot to mention that, alpha' = alpha_2. whereas alpha = alpha_1

I could not find the equation picture of SL conditions of wronskian using psi_m, psi_n and alpha and alpha'.
 

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