SU(2): Get RHS from LHS of Expression

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SUMMARY

The discussion focuses on deriving the right-hand side (RHS) from the left-hand side (LHS) of the expression involving the determinant of a 2x2 matrix using the Levi-Civita symbol. The equation presented is X^{\alpha}_{\ \ \alpha^{\ \prime}}X^{\beta}_{\ \ \beta^{\ \prime}}\epsilon^{\alpha^{\ \prime}\beta^{\ \prime}}=det X\epsilon^{\alpha\beta}, which illustrates the relationship between the determinant and the Levi-Civita symbol. Participants emphasize the importance of writing out a sample case to fully understand the calculation process.

PREREQUISITES
  • Understanding of determinants in linear algebra
  • Familiarity with the Levi-Civita symbol and its properties
  • Basic knowledge of tensor notation
  • Experience with 2x2 matrices and their determinants
NEXT STEPS
  • Study the properties of the Levi-Civita symbol in detail
  • Practice calculating determinants of various matrices
  • Explore tensor notation and its applications in physics
  • Review examples of determinants in the context of SU(2) representations
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This discussion is beneficial for students and researchers in mathematics and physics, particularly those studying linear algebra, tensor calculus, and group theory related to SU(2) symmetry.

intervoxel
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Please, I'm stuck. How to get the rhs from the lhs?

[itex] X^{\alpha}_{\ \ \alpha^{\ \prime}}X^{\beta}_{\ \ \beta^{\ \prime}}\epsilon^{\alpha^{\ \prime}\beta^{\ \prime}}=det X\epsilon^{\alpha\beta}[/itex]
 
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That is one of the definitions of a determinant. The left-hand side is just how you would calculate the value of a determinant. In your case, it is the determinant of a 2 x 2 matrix. Write out a sample case and you will see how it works.
 
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