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In Howard Georgi's Lie Algebras in Particle Physics (and other texts I'm sure), it is determined that the Pauli matrices, \sigma_1 \sigma_2 and \sigma_3, in 2 dimensions form an irreducible representation of the SU(2) algebra.
This is a bit confusion to me. The SU(2) algebra is given by
\left[ J_j, J_k \right] = i\epsilon_{jkl}J_l ,
where J_i are the generators. Meanwhile, the Pauli matrices satisfy:
\sigma_a \sigma_b = \delta_{ab} + i\epsilon_{abc} \sigma_c .
But this implies that the zero generator gets mapped to the identity operator in the spin-1/2 SU(2) representation, because \left[ J_a, J_a \right] = 0, while \sigma_a \sigma_a = 1.
Isn't it a condition for any representation of an algebra for the identity element in the algebra to get mapped to the identity operator?
Thanks for any help.
This is a bit confusion to me. The SU(2) algebra is given by
\left[ J_j, J_k \right] = i\epsilon_{jkl}J_l ,
where J_i are the generators. Meanwhile, the Pauli matrices satisfy:
\sigma_a \sigma_b = \delta_{ab} + i\epsilon_{abc} \sigma_c .
But this implies that the zero generator gets mapped to the identity operator in the spin-1/2 SU(2) representation, because \left[ J_a, J_a \right] = 0, while \sigma_a \sigma_a = 1.
Isn't it a condition for any representation of an algebra for the identity element in the algebra to get mapped to the identity operator?
Thanks for any help.