Subspace Questions: Determine Sets in R2

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The discussion revolves around determining whether specific sets form subspaces of R2. The first set, defined by the condition |X1| = |X2|, fails to be a subspace because the sum of two elements, (1, 1) and (1, -1), does not satisfy the condition, as (2, 0) does not meet the requirement. Similarly, the second set, where (X1)^2 = (X2)^2, also does not form a subspace for the same reason, as the sum of (1, 1) and (1, -1) results in (2, 0), which does not satisfy the condition. The key to determining subspaces is checking if the subset contains the zero vector and is closed under addition and scalar multiplication. The conclusion emphasizes the importance of verifying these criteria to establish whether a subset is a subspace.
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Homework Statement


Determine whether the following sets form subspaces of R2:

{ (X1, X2) | |X1| = |X2| }
{ (X1, X2) | (X1)^2 = (X2)^2 }

Homework Equations





The Attempt at a Solution


I'm clueless. I've been trying to figure it out for a good thirty minutes on both of them, but I'm completely stuck.
 
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How can you tell if some subset of a vector space is a subspace of that vector space?
 
You check to see if there's a counterexample and/or if it's closed under addition/multiplication. Problem is my book has given no examples of something like these, and my professor went over it the day I was out of class so I have no idea how to work it out.

Edit:
Okay, I've figured out the first. I took (1, 1) and (1, -1) which are a part of the subspace, but their sum is not (i.e. (2,0) fails since x1 =/= x2)). I could still use help on the second though!
 
Last edited:
There is a list of axioms, the vector space axioms, somewhere in your book. A subset of a vector space is a subspace iff it is a vector space in its own right, under the same operations.

So all you need to do is check the axioms.
 
Nevermind, I used my above example (1, 1) and (1,-1) for the second question and figured it out!

(1, -1) is a part of the subspace, and so is (1, 1), but their sum is not (2,0) (i.e. 2^2 =/= 0^2)
 
Tinyboss said:
There is a list of axioms, the vector space axioms, somewhere in your book. A subset of a vector space is a subspace iff it is a vector space in its own right, under the same operations.

So all you need to do is check the axioms.

If you need to show that some space and two operations are a vector space, yes, you have to verify all 10 axioms.

OTOH, if you are given a subset of a vector space (R2 in the OP's problem), all you need to do is check that 0 is in the subset, and that the subset is closed under vector addition and scalar multiplication.
 
Mooey said:
You check to see if there's a counterexample and/or if it's closed under addition/multiplication. Problem is my book has given no examples of something like these, and my professor went over it the day I was out of class so I have no idea how to work it out.

Edit:
Okay, I've figured out the first. I took (1, 1) and (1, -1) which are a part of the subspace, but their sum is not (i.e. (2,0) fails since x1 =/= x2)). I could still use help on the second though!

Correction to your terminology: (1, 1) and (1, -1) are elements in the subset of R2. You have shown that this subset is not a subspace of R2, so you shouldn't call it a subspace.
 

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