Subspace Questions: Determine Sets in R2

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SUMMARY

This discussion focuses on determining whether specific sets form subspaces of R2. The sets in question are defined as { (X1, X2) | |X1| = |X2| } and { (X1, X2) | (X1)2 = (X2)2 }. The first set is proven not to be a subspace since the sum of (1, 1) and (1, -1) yields (2, 0), which does not satisfy the condition |X1| = |X2|. Similarly, the second set is also shown not to be a subspace as (1, 1) and (1, -1) produce (2, 0), violating the condition (X1)2 = (X2)2.

PREREQUISITES
  • Understanding of vector spaces and their properties
  • Familiarity with the axioms of vector spaces
  • Knowledge of operations in R2 (addition and scalar multiplication)
  • Ability to identify counterexamples in mathematical proofs
NEXT STEPS
  • Study the vector space axioms in detail
  • Learn about closure properties in vector spaces
  • Explore examples of subspaces in Rn
  • Practice identifying subspaces using various sets in R2
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Students of linear algebra, mathematicians analyzing vector spaces, and educators teaching the concepts of subspaces in R2.

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Homework Statement


Determine whether the following sets form subspaces of R2:

{ (X1, X2) | |X1| = |X2| }
{ (X1, X2) | (X1)^2 = (X2)^2 }

Homework Equations





The Attempt at a Solution


I'm clueless. I've been trying to figure it out for a good thirty minutes on both of them, but I'm completely stuck.
 
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How can you tell if some subset of a vector space is a subspace of that vector space?
 
You check to see if there's a counterexample and/or if it's closed under addition/multiplication. Problem is my book has given no examples of something like these, and my professor went over it the day I was out of class so I have no idea how to work it out.

Edit:
Okay, I've figured out the first. I took (1, 1) and (1, -1) which are a part of the subspace, but their sum is not (i.e. (2,0) fails since x1 =/= x2)). I could still use help on the second though!
 
Last edited:
There is a list of axioms, the vector space axioms, somewhere in your book. A subset of a vector space is a subspace iff it is a vector space in its own right, under the same operations.

So all you need to do is check the axioms.
 
Nevermind, I used my above example (1, 1) and (1,-1) for the second question and figured it out!

(1, -1) is a part of the subspace, and so is (1, 1), but their sum is not (2,0) (i.e. 2^2 =/= 0^2)
 
Tinyboss said:
There is a list of axioms, the vector space axioms, somewhere in your book. A subset of a vector space is a subspace iff it is a vector space in its own right, under the same operations.

So all you need to do is check the axioms.

If you need to show that some space and two operations are a vector space, yes, you have to verify all 10 axioms.

OTOH, if you are given a subset of a vector space (R2 in the OP's problem), all you need to do is check that 0 is in the subset, and that the subset is closed under vector addition and scalar multiplication.
 
Mooey said:
You check to see if there's a counterexample and/or if it's closed under addition/multiplication. Problem is my book has given no examples of something like these, and my professor went over it the day I was out of class so I have no idea how to work it out.

Edit:
Okay, I've figured out the first. I took (1, 1) and (1, -1) which are a part of the subspace, but their sum is not (i.e. (2,0) fails since x1 =/= x2)). I could still use help on the second though!

Correction to your terminology: (1, 1) and (1, -1) are elements in the subset of R2. You have shown that this subset is not a subspace of R2, so you shouldn't call it a subspace.
 

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