Substance's Solubility, Acids, and Bases

Click For Summary
SUMMARY

The solubility of a substance in aqueous acid or base is fundamentally explained by the dissociation of ionic solutes. When a weak acidic organic compound interacts with a strong base, it forms a basic salt that exhibits greater solubility in the aqueous base compared to pure water. Conversely, weak basic organic compounds demonstrate increased solubility in aqueous acids. Understanding these principles is essential for evaluating solubility in the context of ionic equilibria.

PREREQUISITES
  • Ionic solubility principles
  • Chemical equations involving weak acids and bases
  • Solubility product constants (Ksp)
  • Concepts of ionic equilibria
NEXT STEPS
  • Study the dissociation of ionic compounds in aqueous solutions
  • Learn about solubility product constants (Ksp) and their applications
  • Explore examples of weak acids and bases in chemical reactions
  • Investigate the role of pH in solubility and chemical equilibria
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical research or education, particularly those focusing on solubility and ionic equilibria.

Soaring Crane
Messages
461
Reaction score
0
What principle explains the solubility of a substance in aqueous acid or aqueous base?

Ionic solutes and its dissociation is involved in a substance's solubility in an aqueous acid or base. This solubility can be expressed by a chemical equation in which a basic salt results when a a weak acidic organic compound is in the presence of a strong base. This basic salt is then more soluble in the aqueous base than in water. A weak basic organic compound would then be more soluble in an aqueous acid.

I don't know if this correctly/completely explains the substance's solubility.

Thanks for any help.
 
Physics news on Phys.org
1. If quoting from a source, please include a reference to the source.

2. Typically you are taught to evaluate solubilities during some part of the chapter on Ionic Equilibria

3. If you are already aware of solubility products and know how to evaluate them, we can go over the example you've quoted above to prove that it is true. If not, you'll have to either wait till you get to this in school, or learn it by yourself.
 
As Gokul has mentioned, if this is a homework question, its probably asking for your understanding of an equation. Hint: strong base, strong acid, weak base, weak acid, etc
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 48 ·
2
Replies
48
Views
9K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K