MHB Sum of 100 Terms: Prove At Least 2 Numbers Equal

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The natural numbers $a_1,\,a_2,\,\cdots,\,a_{100}$ are such that

$\dfrac{1}{\sqrt{a_1}}+\dfrac{1}{\sqrt{a_1}}+\cdots+\dfrac{1}{\sqrt{a_1}}=20$.

Prove that at least two of the numbers are equal.
 
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Hi, anemone
I´d expected the sum to be: $\frac{1}{\sqrt{a_1}}+\frac{1}{\sqrt{a_2}}+...+\frac{1}{\sqrt{a_{100}}}$
- or am I wrong??
 
anemone said:
The natural numbers $a_1,\,a_2,\,\cdots,\,a_{100}$ are such that

$\dfrac{1}{\sqrt{a_1}}+\dfrac{1}{\sqrt{a_1}}+\cdots+\dfrac{1}{\sqrt{a_1}}=20$.

Prove that at least two of the numbers are equal.

Ops...typo...again...sorry folks!:o

The problem should read:

The natural numbers $a_1,\,a_2,\,\cdots,\,a_{100}$ are such that

$\dfrac{1}{\sqrt{a_1}}+\dfrac{1}{\sqrt{a_2}}+\cdots+\dfrac{1}{\sqrt{a_{100}}}=20$.

Prove that at least two of the numbers are equal.
 
A hint is requested :o
 
lfdahl said:
A hint is requested :o

Hello MHB!

Something irritating has happened to my laptop and it seems like the folder that contains all challenging problems that I have collected from all over the world is ... gone...(Sweating):mad:(Worried)

I will post back for any update on my effort to save the situation and for this challenge problem, I am afraid I may need some decent time to look for its source so I could post a hint based on the suggested solution I found online...sorry folks!
 
anemone said:
Ops...typo...again...sorry folks!:o

The problem should read:

The natural numbers $a_1,\,a_2,\,\cdots,\,a_{100}$ are such that

$\dfrac{1}{\sqrt{a_1}}+\dfrac{1}{\sqrt{a_2}}+\cdots+\dfrac{1}{\sqrt{a_{100}}}=20$.

Prove that at least two of the numbers are equal.
let $a_1\neq a_2\neq a_3\neq ----------\neq a_{100}----(1)$
$$S=\dfrac {1}{\sqrt 1}+\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{3}}+\dfrac{1}{\sqrt{4}}+\dfrac{1}{\sqrt{5}}+----+\dfrac{1}{\sqrt{100}}
<1+\int_{1}^{100}\dfrac{dx}{\sqrt{x}}=1+18=19--(2)$$
but we are given $S=20---(3)$
a contradiction between (2) and (3)
(1) is impossible
so at least two of the numbers are equal
 
Last edited:
Albert said:
let $a_1\neq a_2\neq a_3\neq ----------\neq a_{100}----(1)$
$$S=\dfrac {1}{\sqrt 1}+\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{3}}+\dfrac{1}{\sqrt{4}}+\dfrac{1}{\sqrt{5}}+----+\dfrac{1}{\sqrt{100}}
<1+\int_{1}^{100}\dfrac{dx}{\sqrt{x}}=1+18=19--(2)$$
but we are given $S=20---(3)$
a contradiction between (2) and (3)
(1) is impossible
so at least two of the numbers are equal

Very well done Albert!(Cool)
 

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