MHB Sum of an Indexed Family of Submodules - Northcott, pages 8-9

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Northcott's book defines the sum of an indexed family of submodules, denoted as the sum of the submodules \( L_i \), which is the smallest submodule containing each \( L_i \). To demonstrate that this sum is indeed the smallest submodule, one can consider any submodule \( K \) of \( N \) that contains all \( L_i \). By showing that any element \( x \) in the constructed sum can be expressed as a finite sum of elements from the \( L_i \) and thus must also belong to \( K \), it follows that the sum is contained within \( K \). Therefore, since \( K \) was arbitrary, the constructed sum is confirmed as the smallest submodule containing all the summands. This establishes the clarity of Northcott's claim regarding the sum of the indexed family of submodules.
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I am reading D. G. Northcott's book, Lessons on Rings, Modules and Multiplicities.

On pages 8 and 9, Northcott defines/describes the sum of an indexed family of submodules, as follows:https://www.physicsforums.com/attachments/3507
View attachment 3508At the conclusion of the above text on the construction of the sum of an indexed family of submodules, Northcott writes the following:
" ... ... The submodule $$L$$ which has just been constructed, is called the sum of the $$L_i $$ and is denoted $$\sum_{i \in I} L_i$$. Not only does the sum contain each of the summands $$L_i$$, but it is clearly the smallest submodule of $$N$$ which has this property. ... ... "
Now it is not immediately obvious to me why the sum constructed as above, should be, as Northcott claims, 'clearly' the smallest submodule that contains each of the summands.

Can someone please show me (formally and rigorously) exactly why the sum of an indexed family of modules, constructed as above, should be (clearly) the smallest submodule containing each of the summands?

Help will be appreciated ... ...

Peter
 
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Peter said:
I am reading D. G. Northcott's book, Lessons on Rings, Modules and Multiplicities.

On pages 8 and 9, Northcott defines/describes the sum of an indexed family of submodules, as follows:https://www.physicsforums.com/attachments/3507
View attachment 3508At the conclusion of the above text on the construction of the sum of an indexed family of submodules, Northcott writes the following:
" ... ... The submodule $$L$$ which has just been constructed, is called the sum of the $$L_i $$ and is denoted $$\sum_{i \in I} L_i$$. Not only does the sum contain each of the summands $$L_i$$, but it is clearly the smallest submodule of $$N$$ which has this property. ... ... "
Now it is not immediately obvious to me why the sum constructed as above, should be, as Northcott claims, 'clearly' the smallest submodule that contains each of the summands.

Can someone please show me (formally and rigorously) exactly why the sum of an indexed family of modules, constructed as above, should be (clearly) the smallest submodule containing each of the summands?

Help will be appreciated ... ...

Peter

Let $K$ be a submodule of $N$ such that $K \supseteq L_i$ for all $i\in I$. The goal is to show that $L \subseteq K$. Then since $K$ was arbitrary and $L$ is itself a submodule of $N$ containing each $L_i$, $L$ must be the smallest submodule of $N$ relative to the property of containing all the $L_i$.

Let $x \in L$. Then $x = \sum_{i\in I} x_i$, where $x_i \in L_i$ and $x_i = 0$ for all but finitely many $i$. Let $J = \{i\in I : x_i \neq 0\}$. Then $J$ is a finite set and $x = \sum_{j\in J} x_j$. Since $x_j \in L_j \subseteq K$ for all $j\in J$ and closure under addition holds in $K$, $x \in K$. Hence, $L \subseteq K$.
 
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