Sum of First 20 Terms of Arithmetic Progression with Even Terms Removed

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SUMMARY

The discussion focuses on calculating the sum of the first 20 terms of an arithmetic progression (AP) with the first term as 3 and a common difference of 4, after removing the terms in even positions. The sum is derived using the formula for the sum of an arithmetic progression, resulting in a total of 1580. The odd-numbered terms form a new AP with 10 terms, where the first term remains 3 and the common difference is 8. The calculations confirm the correctness of the approach and the final result.

PREREQUISITES
  • Understanding of arithmetic progression (AP) concepts
  • Familiarity with the formula for the sum of an arithmetic progression: S_n = n/2 * (2a + (n-1)d)
  • Ability to calculate specific terms in an arithmetic progression using T_n = a + (n-1)d
  • Basic algebraic manipulation skills
NEXT STEPS
  • Learn how to derive the sum of an arithmetic progression with varying first terms and common differences
  • Explore the implications of removing terms from sequences in mathematical contexts
  • Study the properties of odd and even indexed terms in sequences
  • Investigate related mathematical concepts such as geometric progressions and their sums
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Students, educators, and anyone interested in understanding arithmetic progressions and their applications in mathematics.

mathlearn
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First term of the progression is 3 & the common difference is 4

Find the sum of the first 20 terms of the progression that is obtained by removing the terms in the even positions of the given progressions, such as the second term,fourh term, sixth term.

Formula preferences

For the sum of an arithmetic progression I prefer,

$S_n=\frac{n}{2}\left\{2a+(n-1)d\right\}$

For the term of an arithmetic progression,

$T_n=a+(n-1)d$

Many Thanks :)
 
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Hint: What is the difference between the first and third terms? What is the difference between the third and fifth terms?
 
greg1313 said:
Hint: What is the difference between the first and third terms? What is the difference between the third and fifth terms?

The third term

$T_3=3+(3-1)4=8+3=11$

The difference between the first and the third term is $3 {\underbrace{\phantom{2d) + (3e}}_{\text{+8}}} 11$

The fifth term

$T_5=3+(5-1)4=16+3=19$

The difference between the first and the third term is $11 {\underbrace{\phantom{2d) + (3e}}_{\text{+8}}} 19$

So there is a common difference of 8 between the terms

$S_{20}=\frac{20}{2}\left\{2*3+(20-1)8\right\}$
$S_{20}=10\left\{6+19*8\right\}$
$S_{20}=10\left\{6+152\right\}$
$S_{20}=10\left\{158\right\}$
$S_{20}=1580$

Correct ?

Many Thanks ;)
 
How many terms are there in the sequence of odd-numbered terms?
 
From the first 20 term the number of odd numbers would be 10. (Thinking)
 
So you've got an arithmetic sequence with ten terms. What is the first term? What is the common difference?
 
greg1313 said:
So you've got an arithmetic sequence with ten terms. What is the first term? What is the common difference?

The first term is 3 & the common difference as calculated above is +8.

Find the sum of the first 20 terms of the progression that is obtained by removing the terms in the even positions of the given progressions, such as the second term,fourh term, sixth term.

And I guess you are supposed to find the sum of first 20 terms of the above arithmetic progression in which all the 20 terms are odd numbers (Thinking)
 
mathlearn said:
The third term

$T_3=3+(3-1)4=8+3=11$

The difference between the first and the third term is $3 {\underbrace{\phantom{2d) + (3e}}_{\text{+8}}} 11$

The fifth term

$T_5=3+(5-1)4=16+3=19$

The difference between the first and the third term is $11 {\underbrace{\phantom{2d) + (3e}}_{\text{+8}}} 19$

So there is a common difference of 8 between the terms

$S_{20}=\frac{20}{2}\left\{2*3+(20-1)8\right\}$
$S_{20}=10\left\{6+19*8\right\}$
$S_{20}=10\left\{6+152\right\}$
$S_{20}=10\left\{158\right\}$
$S_{20}=1580$

Correct ?

Many Thanks ;)

That's correct! Good work!

(I initially misread the problem ... :o)
 

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