Sum of Geometric Series with cosine?

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SUMMARY

The discussion focuses on determining the convergence of the series defined by the expression pi^(n/2)*cos(n*pi) as n approaches infinity. Participants confirm that the series diverges due to the alternating nature of the cosine function, which yields values of 1 and -1, leading to the conclusion that the ratio r = -pi exceeds 1. The D'Alembert's rule is suggested as a method for analyzing convergence, reinforcing the understanding of series behavior in mathematical analysis.

PREREQUISITES
  • Understanding of geometric series and their convergence criteria
  • Familiarity with the Squeeze Theorem in calculus
  • Knowledge of D'Alembert's ratio test for series convergence
  • Basic trigonometric functions, specifically the behavior of cosine
NEXT STEPS
  • Study the application of D'Alembert's ratio test in detail
  • Explore the properties of geometric series and their convergence
  • Investigate the Squeeze Theorem and its applications in series analysis
  • Learn about the behavior of trigonometric functions in series contexts
USEFUL FOR

Students in mathematics, particularly those studying calculus and series convergence, as well as educators looking for examples of series analysis techniques.

dan38
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Homework Statement


With a series like:
pi^(n/2)*cos(n*pi)

How am I meant to approach this?
Do I use the Squeeze Theorem?


Homework Equations





The Attempt at a Solution

 
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I believe you are trying to find the sum as n->infinity?

If so, you should start by checking whether the series converges or diverges.
 
Hi dan38
As Infinitum suggested, you probably are looking for convergence/divergence of the serie
I suppose you are being confused by the cos 'trick'.
But look at is closely.. what possible values do you have for cos(n∏) ?
1, -1, 1, -1, ... that is, (-1)^n
Are you familiar with D'Alembert's rule to decide on convergence ?

Cheers...
 
ah I see
so then it would become

(pi)^0.5 * (pi)^n * (-1)^n

pi^0.5 * ( - pi )^n

-pi^1.5 * ( - pi )^(n-1)

Of the form required
where a = -pi^1.5 and r = -pi

since r > 1
then it is divergent?
 
Well you're notation is confusing, you are supposed to use absolute values and somehow you get to -∏,
but yes, you would get to ∏>1 and therefore it diverges

Cheers...
 

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