Sum of Getometric Sequence with alternating signs

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Homework Help Overview

The discussion revolves around the sum of a geometric sequence with alternating signs, specifically the expression 5^2 - 5^3 + 5^4 - ... + (-1)^k*5^k, where k is an integer greater than or equal to 2.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the formula for the sum of a geometric series and discuss how to adapt it for a sequence starting from r^2 instead of r^0. There are attempts to manipulate the formula to account for the alternating signs and the starting index.

Discussion Status

Some participants have provided guidance on how to handle the starting point of the series and the implications of the alternating signs. Multiple interpretations of the sum's formulation are being explored, but there is no explicit consensus on the final approach.

Contextual Notes

There is a mention of the need to adjust the standard geometric series formula due to the specific starting index and the alternating nature of the terms. Participants are also considering the implications of including or excluding certain terms in their calculations.

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Homework Statement



5^2 - 5^3 + 5^4 - ... + (-1)^k*5^k whre k is an integer with k >= 2

Homework Equations




The Attempt at a Solution



I know (5^(k-1) - 5^2)/2 gives you the sum if they were all positive. I tried multiplying it by (-1)^k or something but that just changes the sign. I wish I could give you more but I can't.
 
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A geometric sequence is [itex]\sum_{n=0}^N ar^n[/itex]. And the sum is:
[tex]\frac{1- r^{N+1}}{1- r}[/tex]
r does not have to be positive. Your sequence has a= 1, r= -5.
 
[tex]\frac{1- (-5)^{2+1}}{1- (-5)}[/tex] = 21 though and not 25
 
Last edited:
The sum that HallsofIvy gave includes (-5)0 and (-5)1
 
There are two ways to handle the fact that your sum starts with [itex]r^2[/itex] rather than [itex]r^0= 1[/itex].

1) Factor out an [itex]r^2[/itex] [itex](-5)^2+ (-5)^3\cdot\cdot\cdot+ (-5)^k= (-5)^2(1+ (-5)+ \cdot\cdot\cdot+ (-5)^{k-2})[/itex]

Use the formula I gave with n= k- 2 and then multiply by [itex](-5)^2= 25[/itex].

2) Use the formula with n= k and then subtract of [itex](-5)^0+ (-5)^1= 1- 6= -4[/itex].
 

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