SpaceTiger
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It isn't, really, but it can be used as a justification for the application of Newton's Laws to the problem. Without giving the light a mass, you effectively have action without reaction (the Newtonian gravitational force would have to be set to zero).RandallB said:How is the photon or light’s 'mass' h\nu/c^2 helpful.
By the way, I made a mistake in my latex code in an earlier post (forgot to include the \frac). Here's the correct expression for the semilatus rectum:
p=\frac{v^2r_0^2}{GM}
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