Sun Shrink: What Would Happen to Sun's Color?

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SUMMARY

The discussion centers on the implications of a hypothetical scenario where the Sun suddenly shrinks in size. Participants agree that a decrease in the Sun's radius would likely result in a bluer appearance due to increased energy consumption and temperature changes. The mass-luminosity relationship and the Stefan-Boltzmann law are referenced to explain how luminosity and temperature affect the color of stars. The conversation highlights the importance of defining "shrink" in a physical context, as it can lead to different interpretations of the Sun's behavior.

PREREQUISITES
  • Understanding of the mass-luminosity relationship in astrophysics
  • Familiarity with the Stefan-Boltzmann law
  • Knowledge of Wien's law for blackbody radiation
  • Basic concepts of stellar evolution, including red giant stages
NEXT STEPS
  • Research the mass-luminosity relationship and its implications for stellar color
  • Study the Stefan-Boltzmann law and its application in astrophysics
  • Explore Wien's law and its relevance to blackbody radiation
  • Investigate the stages of stellar evolution, particularly the transition to red giants
USEFUL FOR

Astronomy students, astrophysicists, and anyone interested in stellar dynamics and the physical laws governing star color and luminosity.

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what do you think would happen to the colour of the sun if it suddenly shrank in size?
 
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I seriously doubt it would happen, but with a smaller surface area to radiate energy, and assuming energy is still being produced, it would look more blue or white.
 
Would its mass remain the same?

You said "shrunk", so I'm assuming yes.

I'm guessing it would get brighter because the fuel would be burning more rapidly to resist gravitation...?
 
Ooops, you said "colour". Missed that...

Another wild guess, but it might look "bluer"...
 
It is is nearly impossible to give a meaningful answer to this question. The word shrink is not well defined in the world of Physics so it is not clear what you mean. There are several ways the sun could shrink. As it burns the supply of Hydorgen the nuclear fires will cool, this means that gravitation will gain the upper hand and cause the sun to "shrink" the cooler temperatures will mean that the sun will be a bit redder.

Now, what do you mean by shrink?
 
I think he/she means "decrease in size" and not by any natural methods, but just... well, just "shrink".

Can't say I like this because he/she is asking us to drop some important physical laws, exactly the ones that are needed for the correct answer...
 
Originally posted by Tail
I think he/she means "decrease in size"
...which is still meaningless. Volume or mass?
 
Can't say I like this because he/she is asking us to drop some important physical laws, exactly the ones that are needed for the correct answer...

first of all, tail, may i tell you that this was my first post. it should have gone in the homework help section. if you think i am looking for an answer you are correct, but not directly from you. I'm sorry if you think i am just looking for a quick answer. perhaps i should have written up what i think about the question so far too...

sorry about the ambiguity of the word 'shrink', but what i think it is referring to is a sudden lessening of the radius due to reason 'x'. think of it just becoming more dense. russ_watters, decrease in volume.

so by using that approach, what i have thought up so far is that energy consumption would increase, there fore as tail mentioned, the colour would be 'bluer'.
could i also include the red giant stage of a star in its life as an argument. as the star increases in size, less denser, it appears 'redder'?

sorry again if this may appear to be an attempt to get quick answers, hope you understand:smile:
 
The color is basically a function of mass and radius (or temperature, see later)

The mass-luminosity relationship states

Lstar=M3.5star in units of Lsun and Msun.

Now we find the flux E = Lstar/area

E = Lstar/4[pi]r2

From there, the total radiation given off per meter2 = the Stephan-Boltzmann constant times the themperature4 or


Tstar= {E/[sig]}1/4

now replacing E with Lstar/4[pi]r2 we see

Tstar= {Lstar/4[pi]r2[sig]}1/4.

Next, we use Wien's law to see [lamb]max=3,000,000/Tstar in nm

So, given mass and radius we can calculate the wavelength of maximum emission of the star by

[lamb]max=3,000,000 / (Lstar/4[pi]r2[sig]}1/4).

and recall that:Lstar=M3.5star

and finally we obtain :

[lamb]max=3,000,000 / (M3.5star/4[pi]r2[sig]}1/4)

where we only need mass and radius and

where:

M= mass
L=luminosity (both in unts of the sun)
[sig]= Stephan-Boltzmann constant
[lamb]max= wavelength of maximum emission in nano meters.

We find that the reddest stars are cool and big, large hot stars are blue, and small hot stars are white.

Of course, astronomers are lazy and would just look at a http://www.astro.ubc.ca/~scharein/a311/Sim/hr/HRdiagram.html



I also need to point out that there are different ways to go about finding the answer depending on what information is given.. Note that mass is the most important measurment we can get. If we know the mass or the (absolute bolometric) luminosity then we can find the radius if we know temperature and vica versa. To know the mass or luminosity we really need a spectroscopic binary or an eclipsling binary, respectivly. But our most accurate measurment of luminosity comes from mass, as it is not possiblt to know exactly how much extinction occurs. We do know stars gain about 1.9 magnitudes per 1000 parsecs distance. I say gain beacuse the lower the magnitude a star is, the brighter it is. Maybe I should say they look 1.9 magnitudes fainter.

Does that clarify things a bit? or did I just confuse you even more ?

I think this is correct, or I hope someone will at least notice and correct me. I may be missing somthing about some of this only applying to main sequence stars. This was a nice refresher, so I'm sure I'm still forgetting much right now.
 
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  • #10
I'm sorry, I didn't mean to be impolite... just tired I guess...
 
  • #11
I'm sorry, I didn't mean to be impolite... just tired I guess...
no need to apologise tail. i appreciate u giving up ur time to help individuals like me

radioactive waves, i have read through it twice...and unfortunately i don't get it. its late night. i'll go over it tomorrow hopefully and then i'll let u know if there were any certain bits i don't get. thanks for ur help.:smile:
 
  • #12
hi radioactive :smile:

what is flux E?

also how does the finding of (lambda)max help in predicting the colour?
 

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