Superconductor in an external magnetic field

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SUMMARY

The discussion focuses on the behavior of a superconducting spherical shell in a uniform magnetic field, specifically addressing the magnetic field outside the shell and the surface current density. The magnetic field outside the shell is derived using the magnetic dipole moment formula, resulting in the expression for the magnetic field as a function of the external magnetic field and the shell's radius. The surface current density is not directly calculated, leading to a suggestion to use the continuity of tangential magnetic fields to resolve this. The reference to "A Guide to Physics Problems" by Cahn and Nadgorny is provided for further clarification.

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Raihan amin
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Homework Statement


A superconducting spherical shell of radius R is placed in a uniform magnetic field ##\vec{B_0}##
1)Find the magnetic field everywhere outside the shell
2)the sutface current density

Homework Equations


Inside the shell the net magnetic field is 0, and at the surface also.
The magnetic field of a magnetic diople of moment ##\vec{m}## is
$$\vec{B_m}=\frac{μ_0}{4\pi}[\frac{3(\vec{m}.\vec{r})\vec{r}}{r^5} - \frac{\vec{m}}{r^3}]$$

The Attempt at a Solution



The boundary condition at the surface which is at an angle ##\theta## with the vertical is
$$\vec{B_{0,\hat{n}}}+\vec{B_{m,\hat{n}}}=0$$
So,$$B_0\cos{\theta}+\frac{μ_0}{4\pi}(\frac{2m\cos{\theta}}{R^3} )=0$$
Therefore at $$\vec{m}=-(\frac{2\pi}{μ_0})R^3 \vec{B_0} $$,the boundary condition are satisfied on the surface of the shell.Hence,$$\vec{B}=\vec{B_0}-\frac{(3R^3)(\vec{B_0}.\vec{r})\vec{r}}{2r^5} + \vec{B_0}(\frac{R^3}{2r^3})$$
But i can't find the surface current density in this way. In my textbook,the author has written that we can find that using tangential B's continuity though i didn't get that.
 
Last edited:
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You calculated m as function of B and then plugged in m as function of B again (and I'm a bit surprised the terms don't cancel). You need m as function of the rotation of the surface current.
 
mfb said:
You calculated m as function of B and then plugged in m as function of B again (and I'm a bit surprised the terms don't cancel). You need m as function of the rotation of the surface current.
I know that way,but it is also a valid process i think.
You can see page 305 of "A Guide to Physics Problems" by Cahn and Nadgorny
 
Here it is
 

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