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Suppose x is a discrete, binomial random variable

  1. Oct 20, 2006 #1
    How do I do this p(x<1) this sign has a _ under the <
    n=6 p=0.1




    Suppose x is a discrete, binomial random variable.

    Calculate P(x > 2), given trails n = 8, success probability p = 0.3

    [Hint: P(x > value) = 1 – P(x <= value) <= is a < with a _ under it

    (tell me the number value you get)




    Please I need help !
     
  2. jcsd
  3. Oct 20, 2006 #2

    radou

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    A binomial random variable distribution is given by [tex]f(x)=\left( \begin{array}{c} n \\ x \end{array} \right) p^x (1-p)^{n-x}[/tex]. That's a starting point.

    Edit: one more hint - the probability that a discrete random variable will have a value less or equal x is [tex]F(x) = P(X \leq x) = \sum_{i;x_{i}\leq x}f(x_{i})[/tex].
     
    Last edited: Oct 20, 2006
  4. Oct 20, 2006 #3

    selfAdjoint

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    Use the \le construction in tex. Remove the blanks in the tags here to get it.
    [ tex]p(x \le 1)[/tex ]
    to get
    [tex]p(x \le 1)[/tex]
     
  5. Oct 20, 2006 #4
    Thank you for your help with how to make the symbols.... I also need help with the answers
     
  6. Oct 20, 2006 #5

    radou

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    [tex]P(x > 2) = 1 - P(x \leq 2)[/tex]
    [tex]P(x \leq 2) = \left( \begin{array}{c} 8 \\ 0 \end{array} \right) 0.3^0 (1-0.3)^{8-0} + \cdots[/tex] (sum until x = 2, including that case)

    I hope you know how to carry on now.
     
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