Supposedly simple calculus problem.

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The differential equation presented is separable and can be simplified by factoring out 1/x. The initial attempts involve manipulating the equation into a form suitable for integration, specifically using the substitution u = y/x. Participants emphasize the importance of guiding the original poster along their current method rather than introducing new approaches. The discussion highlights the need for clarity in the integration process and encourages collaboration to reach a solution.
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Homework Statement



Solve the differential equation.

\frac{dy}{dx} = \frac{1}{xy} + \frac{y}{x}

The Attempt at a Solution



\frac{dy}{dx} = \frac{x + xy^{2}}{x^{2}y}

\frac{dy}{dx} = (\frac{x}{x^{2}})(\frac{1 + y^{2}}{y})

(\frac{y}{1 + y^{2}})dy = \frac{x}{x^{2}}dx

\oint\frac{y}{1 + y^{2}}dy = \oint\frac{x}{x^{2}}dx

I can't seem to get any further than there
 
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change variables u=y/x
 
Darth Frodo said:

Homework Statement



Solve the differential equation.

\frac{dy}{dx} = \frac{1}{xy} + \frac{y}{x}


The Attempt at a Solution



\frac{dy}{dx} = \frac{x + xy^{2}}{x^{2}y}
It's simpler to just factor out 1/x, giving
dy/dx = (1/x)(1/y + y) = (1/x)(1 + y2)/y
Darth Frodo said:
\frac{dy}{dx} = (\frac{x}{x^{2}})(\frac{1 + y^{2}}{y})

(\frac{y}{1 + y^{2}})dy = \frac{x}{x^{2}}dx

\int\frac{y}{1 + y^{2}}dy = \int\frac{x}{x^{2}}dx

I can't seem to get any further than there
The first integral can be done with an ordinary substitution. In the integral on the right, simplify x/x2.
 
Try multiplying both sides of your original DE by y.

RGV
 
lurflurf said:
change variables u=y/x

Ray Vickson said:
Try multiplying both sides of your original DE by y.

RGV
Guys, the equation is separable, and the OP is close to getting a solution. IMO, the best thing to do is help him along the path he's on (which is the simplest), rather than steering him in a different direction.
 
Mark44 said:
Guys, the equation is separable, and the OP is close to getting a solution. IMO, the best thing to do is help him along the path he's on (which is the simplest), rather than steering him in a different direction.

I could not see the rest of his submission on my i-phone at the coffee shop, so that's why I replied.

RGV
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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