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Surface area of parabolic sheet

  1. Nov 29, 2007 #1
    Am I correct in saying the surface parameterized by r = (sin v, u, cos v), v = [-pi/2, pi/2], u = [-1, 1] has an area of 2pi ?

    I get something different by computing the arc length of the parabola within the bounds and multiplying by 2.

    Which method is wrong?
  2. jcsd
  3. Nov 29, 2007 #2


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    Sure, but that is not a parabolic sheet, it is the half-shell of a cylinder with radius 1..
  4. Nov 29, 2007 #3
    Hmm.. I see. Thanks.
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