Surface Charges on a Coaxial Cable

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SUMMARY

The discussion focuses on calculating surface charge densities on a coaxial cable using Gauss' Law. Specifically, the user successfully determines the surface charge density ##\sigma_b## by applying a Gaussian surface within the outer conductor, where the electric field is zero. However, the calculation of ##\sigma_c## is problematic due to the lack of information regarding the total charge on the outer cylinder. The consensus is that it is reasonable to assume the outer conductor has no net charge, which simplifies the analysis.

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  • Understanding of Gauss' Law in electrostatics
  • Familiarity with coaxial cable configurations
  • Knowledge of electric field concepts
  • Basic principles of surface charge density
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cpburris
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Homework Statement
A long coaxial cable consists of a conducting inner cylinder of radius ##a## and a thick outer conducting cylinder of inner radius ##b## and outer radius ##c## (Note: ##a<b<c##). The surface charge density on the inner cylinder is ##\sigma##. Find the surface charge densities ##\sigma_b## & ##\sigma_c##.
Relevant Equations
##E_{inside conductor}=0##
Gauss' Law - ##\oint \vec E \cdot d \vec A = \frac {Q_{enclosed}} {\epsilon_0}##
To find ##\sigma_b## I can use a Gaussian surface of a cylinder of length ##L## and radius ##c>r>b##. Since that is inside of the outer conductor, I know the electric field is zero, so I have from Gauss' Law, $$0=2 \pi L\left(b\sigma_b+a\sigma\right)$$ and easily solve for ##\sigma_b##. For ##\sigma_c## however, I am unsure how to proceed. The problem does not give any information about the total charge on the outer cylinder or the coaxial cable as a whole, and it would seem to me that without knowing one of these ##\sigma_c## is arbitrary. Is there something I am missing or is there an issue with the statement of the problem?
 
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Strictly speaking there is the issue that the total charge on the outer conductor is not specified as you correctly pointed out. I think that in this case you may safely assume that the outer conductor bears no net charge.
 

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