Suspending a Weight with 3 Cords: A Puzzle

[fisselt]

Homework Statement

Weight suspended by 3 cords. 1 from the weight goes up vertically to the knot. The next goes left 30° below horizontal and the last goes to the right 45° above horizontal.

Homework Equations

f=ma

The Attempt at a Solution

I don't think I've ever worked a problem with a cord below horizontal. So I'm stumbling a bit.

Since there's only 1 cord above horizontal (T₁) it should carry the whole y force. So, in y T₁=T₂+T₃
And, in x the left and right cords must be equal T₁=T₂


T₁sin(45)=T₂sin(30)+mg

Not sure about the rest. Any help?

 

[OldEngr63]

The problem statement is somewhat confusing. A figure would really help.

 

[fisselt]

Quick picture I just made.

 

[azizlwl]

As the object not going up or down
it's too not going left or right, equal forces must be there to make it in equilibrium.

 

[OldEngr63]

You simply need to sum forces, both horizontal and vertical, at the junction point, and require that both sum to zero. That will give you everything you need.