How Do You Calculate Tension in Multiple Cords Supporting a Single Mass?

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SUMMARY

The discussion focuses on calculating the tension in three cords supporting a 250 N mass under two different configurations. In System 1, Cord A is positioned at 30 degrees below horizontal, and Cord B at 45 degrees below horizontal, while Cord C connects them to the mass. In System 2, Cord A is at 60 degrees to the right of vertical, and Cord B remains at 45 degrees below horizontal. The key takeaway is that to find the tensions, one must resolve the forces into horizontal and vertical components and apply the equilibrium condition that the sum of the forces equals zero.

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Homework Statement


Find the tension in each cord (three cords) in the figure if the weight of the suspended object is 250 N. There are two systems
System 1
Cord A is 30 Degrees below horizontal on the left, Cord B is 45 degrees below Horizontal on the right. Cord C connects the other two cords to the 250 N mass
System 2
Cord A is 60 degrees to the right of vertical. Cord B is 45 degrees below horizontal. Cord C connects the other two cords to the 250 N masss

Homework Equations


I'm not really sure where to start this equation, thought it was T1/sin(30) but that's not it, and without that I'm not sure how to continue
 
Last edited:
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In general you know that if it is not accelerating, in this case not even moving, then the sum of the forces will net to 0.

So draw a diagram and resolve the forces in the tensions into horizontal and vertical components.

If nothing is moving, then the sum of the horizontal forces is 0, and likewise for the vertical.
 

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