MHB Symmetry in the algebraic expressions

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The expression $(x+a+b)(x+b+c)(x+c+a)$ exhibits symmetry in the variables a, b, and c, meaning that switching any two of these variables does not change the overall expression. This is referred to as "cyclic symmetry," where the expression remains invariant under cyclic permutations of the variables. However, it is also described as "fully symmetric," which is a stronger condition; in this case, swapping any pair of variables results in the same expression. An example of a non-fully symmetric expression is $(a - b)(b - c)(c - a)$, which changes sign when two variables are swapped. Understanding these symmetries is crucial for analyzing algebraic expressions and their properties.
NotaMathPerson
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Hello!

I read about the symmetry of the following product

$(x+a+b)(x+b+c)(x+c+a)$ my book says that a, b and c occur symmetrically. Why is that?
 
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NotaMathPerson said:
Hello!

I read about the symmetry of the following product

$(x+a+b)(x+b+c)(x+c+a)$ my book says that a, b and c occur symmetrically. Why is that?

This is also called "cyclic symmetry" and it simply means that if you switch the two variables in any of the 3 pairs in $(a,b,c)$, you still have the same expression. Try it to verify. :)
 
Actually, it's "fully symmetric" which is *different* than cyclic symmetry. To see the difference, consider:

$(a - b)(b - c)(c - a)$

If we send $a \to b \to c \to a$, we get:

$(b - c)(c - a)(a - b)$, which is the same expression (even though the factors are in a different order).

If we just switch $a$ and $b$, we get

$(b - a)(a - c)(c - b) = -(a - b)(b - c)(c - a)$, which is *not* the original expression, but its negative.

That is-if we can swap any pair and get the original expression, it is fully symmetric (permutations are generated by pair-swaps), full symmetry implies cyclic symmetry, but the reverse is not so.

(Note that $(a - b)(b - c)(c - a)$ also remains unchanged under the transformation $a \to c \to b \to a$ which gives:

$(c - a)(a - b)(b - c)$).

The transformation (substitution) $a \to b \to c \to a$ is called a 3-cycle, as it changes 3 things to something else, and repeating it three times "completes the cycle" and leaves you where you were.
 
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