- #1

- 2

- 0

Say:

3x^2 - 2y = i

x + y = j

Solving for x and y in terms of i and j?

Note: This is not a homework problem, just a general question.

- Thread starter D.K
- Start date

- #1

- 2

- 0

Say:

3x^2 - 2y = i

x + y = j

Solving for x and y in terms of i and j?

Note: This is not a homework problem, just a general question.

- #2

Char. Limit

Gold Member

- 1,204

- 14

Here, I would say y=j-x then substitute that in for y.

Say:

3x^2 - 2y = i

x + y = j

Solving for x and y in terms of i and j?

Note: This is not a homework problem, just a general question.

3x^2 - 2(j-x) = i

Solve for x...

[tex]x = \pm \frac{1}{3} \left(\sqrt{6 j+3 i+1}-1\right)[/tex]

Then, knowing what x is, substitute x in the second equation to express y in terms of i and j.

- #3

- 2

- 0

Thanks a lot. For some reason, I have always had difficulty with simple things like these!Here, I would say y=j-x then substitute that in for y.

3x^2 - 2(j-x) = i

Solve for x...

[tex]x = \pm \frac{1}{3} \left(\sqrt{6 j+3 i+1}-1\right)[/tex]

Then, knowing what x is, substitute x in the second equation to express y in terms of i and j.

- #4

- 30

- 0

There are no workable non lin equations that aren't reduced to a sum lin eqautions

blah blah blah

blah blah blah

- #5

- 30

- 0

The real sht is identifying lin equations to reality

- Last Post

- Replies
- 3

- Views
- 833

- Last Post

- Replies
- 4

- Views
- 4K

- Last Post

- Replies
- 1

- Views
- 3K

- Replies
- 2

- Views
- 701

- Replies
- 6

- Views
- 13K

- Last Post

- Replies
- 4

- Views
- 702

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 5

- Views
- 874

- Last Post

- Replies
- 8

- Views
- 986

- Replies
- 1

- Views
- 775