System of linear and non-linear equations

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SUMMARY

The discussion focuses on finding a vector with a magnitude of 5 that is perpendicular to the vectors 3i - 2j + 4k and 4i - 3j - k. The participant derived three equations based on the magnitude and dot product conditions: x² + y² + z² = 25, 3x - 2y + 4z = 0, and 4x - 3y - z = 0. A solution approach was suggested involving substitution and solving simultaneously, but the cross product method was recommended as a more efficient alternative.

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Homework Statement



find the vector with magnitude 5 and perpendicular to 3i-2j+4k and 4i-3j-k

The Attempt at a Solution


lets name the vector component x for the i y for the j and z for the k
i got three equation
1- x^2+y^2+z^2=25 ( magnitude)
2-3x-2y+4z=0
3-4x-3y-z=0 (2, 3 from dot product by the 2 given vectors)
i am supposed to solve those simultaneously, but i can't do it
 
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abdo799 said:

Homework Statement



find the vector with magnitude 5 and perpendicular to 3i-2j+4k and 4i-3j-k

The Attempt at a Solution


lets name the vector component x for the i y for the j and z for the k
i got three equation
1- x^2+y^2+z^2=25 ( magnitude)
2-3x-2y+4z=0
3-4x-3y-z=0 (2, 3 from dot product by the 2 given vectors)
i am supposed to solve those simultaneously, but i can't do it

You could if you tried. Use equation 3 to solve for z in terms of x and y. Substitute that into equation 2 and solve for y in terms of x. Put it all into equation 1 and solve for x. But it would be a lot easier to use the cross product, if you know what that is.
 
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I tried it and it worked, thanks
 

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