Systems of Nonlinear Equations

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Homework Help Overview

The problem involves a wire of 60 feet being cut into two pieces, with the intention of forming one piece into a square and the other into a circle, such that the total area enclosed is 100 square feet. The equations governing the relationship between the lengths of the pieces and their respective areas are also discussed.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the lengths of the wire pieces and their areas, but questions the correctness of their arithmetic and setup after not obtaining a valid solution.
  • Some participants point out typographical errors in the equations and suggest corrections to the relationships between the variables.
  • There is a mention of the quadratic nature of the problem, with inquiries about the solutions derived from it.

Discussion Status

Participants are actively engaging in identifying mistakes in the original poster's setup and calculations. While some guidance has been provided regarding corrections, there is still uncertainty about the validity of the solutions obtained, and the discussion remains open-ended.

Contextual Notes

There are constraints related to the total length of the wire and the requirement for the total area to equal 100 square feet. The original poster expresses confusion about the results of their calculations, indicating potential misunderstandings in the problem setup.

Lurid
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Homework Statement



A wire 60 feet long is cut into two pieces. Is it possible to bend one piece into the shape of a square and the other into the shape of a circle so that the total area enclosed by the two pieces is 100 square feet? If this is possible, find the length of the side of the square and radius of the circle.

Homework Equations



x+y=60, where x is one of the pieces cut, and y is the other.

(x/4)2, which is the area of the square the one of the pieces make.

2∏R=y, which is the circle that the the piece y can make.
R=y/(2∏R)
∏R2=area of a circle
∏(y/(2∏R))2=
y2/(4∏)=

Two Equations:
x+y=100
(x/4)2+y2/(4∏)=100

The Attempt at a Solution



(x/4)2+y2/(4∏)=100
∏x2+4y2 = (100)(∏)(16)

y=60/x

∏x2+4(60/x)2 = (1600)(∏)
∏x4-1600∏x2+14400 = 0

I used the quadratic equation, solved for x and y. I plugged it back in and it didn't work out quite well. Is there anything wrong with my arithmetic or set-up? Or maybe it's impossible?

Any help is greatly, greatly appreciated!
 
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You have two mistakes, although one is typographical:

Lurid said:
Two Equations:
x+y=100

This should be 60, according to the set-up.

y=60/x

According to the above equation, you should have y = 60 - x.
 
Steely Dan said:
You have two mistakes, although one is typographical:



This should be 60, according to the set-up.



According to the above equation, you should have y = 60 - x.

Thanks so much! I can't believe I couldn't catch that.
I still couldn't get a correct answer though (well, it doesn't work because x=74).
 
Lurid said:
Thanks so much! I can't believe I couldn't catch that.
I still couldn't get a correct answer though (well, it doesn't work because x=74).

It's a quadratic equation, so you should get two solutions. What's the other?
 
Steely Dan said:
It's a quadratic equation, so you should get two solutions. What's the other?

It was a negative number, -2.77. I'll just ask my teacher tomorrow. :)
 

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